Answer:
the preview of the scientific method
Answer:
Total work done = 15,306.25 lb.ft
Explanation:
First of all, we know that;
Work done = Force x Distance.
Thus,
Work done to pull bucket (Wb) = 500 x 30 = 15,000 lb.ft
Now, work done by pulling the rope is given as a function of the length of the rope. Thus;
Wr =(x,x=0∫) F(x) dx
=(35,0∫) 0.5x dx
= 0.5[x²/2](35,0)
Thus,Wr = 0.5[(35²/2) - (0²/2)] = 0.5[612.5] = 306.25 lb.ft
Total work done will be the sum of that done to pull the bucket and that done to pull the rope.
Thus, Wt = Wb + Wr
Wt = 15000 + 306.25 = 15,306.25 lb.ft
Answer: R = 28 degree
Explanation:
The given parameters are:
Refractive index n = 1.52
Incident angle I = 45 degree
According to Snell law,
Sin I/Sin R = n
Where
I = angle of incidence
R = angle of refraction
n = refractive index
Substitute all the parameters into the formula
1.52 = sin 45/ sin R
Make sinR the subject of formula
Sin R = sin 45/1.52
Sin R = 0.46520
R = sin^-1(0.46520)
R = 27.72 degree
Therefore, the angle of refraction will be 28 degrees approximately.
Principles of conservation of linear momentum
Kinetic Energy before collision 60kJ
Kinetic Energy after collision 56.76kJ
Explanation:
1. Given data
mass m1= 1000kg
velocity u1= 10m/s
mass m2= 800kg
velocity u2= 5m/s
2. We want to find the common velocity after the collision
Applying the principle of conservation of linear momentum for inelastic collision we have
m1u1+m2u2= (m1+m2)V
substituting and solving for V
1000*10+800*5= (1000+800)V
10000+4000= 1800V
14000=1800V
3. Divide both sides by 1800
V= 14000/1800
V= 7.8m/s
4. Now let us find the kinetic energy of the two cars before the collision
For the first car
KE= 1/2m1u1^2
KE= 1/2*1000*10^2
KE=(1000*100)/2
KE= 100000/2
KE= 50000 Joules
KE= 50 kJ
For the second car
KE= 1/2m2u2^2
KE= 1/2*800*5^2
KE=(800*25)/2
KE= 20000/2
KE= 10000 Joules
KE= 10 kJ
Hence the total kinetic energy before the collision is
=50+10
=60kJ
After collision
KE= 1/2m1V^2
KE= 1/2*1000*7.8^2
KE=(1000*60.84)/2
KE= 60840/2
KE= 32420 Joules
KE= 32.42kJ
For the second car
KE= 1/2m2u^2
KE= 1/2*800*7.8^2
KE=(800*60.84)/2
KE= 48.672/2
KE= 24336 Joules
KE= 24.34 kJ
Hence the total Kinetic energy after collision is
=32.42+24.34
=56.76kJ
See the link below for more information on linear momemtum
https://brainly.in/question/17792506
Answer: is C
Expiation: you can find the answer on quizlet and it’s diverging mirror so the answer is C