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Tems11 [23]
2 years ago
6

Group of physics students are asked to demonstrate Ohm’s Law in parallel circuits.  Using their knowledge of Ohm’s Law and the r

ules governing voltage, current, and resistance in series and parallel circuits they must set up an investigation using batteries, wires, three light bulbs of unknown resistance, a voltmeter, and an ammeter.  Their task is to determine the resistance of each bulb.  Given the equipment at hand, the groups determine that they will collect data to determine the voltage and current at each element in the circuit and use those values to calculate resistance.  Four students offered their suggestions on which measurements must be taken to determine the resistance provided by each bulb.  Which student’s suggestion below would provide enough evidence to be able to determine the value of each resistor? 
​

Physics
1 answer:
astra-53 [7]2 years ago
8 0

The student’s suggestion who provides enough evidence to be able to determine the value of each resistor is student D.

<h3>What is current?</h3>

The current is the stream of charges which flow inside the conductors when connected across the end of voltage.

For the given set of parallel resistors, we need to find the resistance of each resistor.

From the Ohm's law, V =IR

R = V/I

Resistance value depends upon the voltage difference across the resistor and the current flowing through that resistance.

Thus, the student D gives enough evidence to find resistance of the circuit is

Learn more about current.

brainly.com/question/10677063

#SPJ1

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Answer:

Comparison Microscope

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7 0
3 years ago
Two long, parallel wires are attracted to each other by a force per unit length of 350 µN/m. One wire carries a current of 22.5
pishuonlain [190]

Answer

given,

force per unit length = 350 µN/m

current, I = 22.5 A

y = y = 0.420 m

\dfrac{F}{L}= \dfrac{KI_1I_2}{d}

I_2 = \dfrac{F}{L}\dfrac{d}{KI_1}

I_2 = 350\times 10^{-6}\times \dfrac{0.42}{2 \times 10^{-7}\times 22.5}

    I₂ = 32.67 A

distance where the magnetic field is zero

\dfrac{4\pi \times 10^{-7}\times 32.67}{2\pi y_1}=\dfrac{4\pi \times 10^{-7}\times 22.5}{2\pi (0.42-y_1)}

y_1 = 0.248\ m

there the distance at which the magnetic field is zero in the two wire is at 0.248 m.

3 0
3 years ago
If an exit sign is hanging from the ceiling by three chains each of which has a tension of 15N what is the weight of the sign
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3 years ago
Which statement is True ?
Over [174]
A is the correct answer.
4 0
3 years ago
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