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aivan3 [116]
3 years ago
13

You are testing a vehicle fuel gauge float. The float pulls 40mA when the tank is 100% full and 2mA when the tank is empty. Assu

ming that the float's resistance scales linearly between 0% and 100% full, what current draw in milliamps should we see if we set the float to 49% full? Give your answer to the tenth of a milliamp.
Physics
1 answer:
Ad libitum [116K]3 years ago
3 0

Answer:

I=20.6mA

Explanation:

the relation between the current and the tank percentage is linear:

\frac{40mA-2mA}{100-0} = \frac{I-2mA}{49-0}

then:

I=49*38/100+2=20.6mA

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A 10 kg rock that has been dropped from a 60 meter high cliff experiences an average force of air resistance of 30 N. Calculate
lesya692 [45]

Answer:

4086 J

Explanation:

The potential energy is transformed to kinetic energy less the frictional energy. Potential energy= mgh where m represent mass, g is acceleration due to gravity and h is the height of cliff

Since we have force of air resistance, work done due to air resistance will be product of force and distance

mgh-Fh= 0.5mv^{2}= KE

Substituting 10 Kg for m, 9.81 for g and 60 m for F then the kinetic energy at the bottom will be

KE= 10*9.81*60- (30*60)=4086 J

8 0
3 years ago
Jason applies a force of 4.00 newtons to a sled at an angle 62.0 degrees from the ground. What is the component of force effecti
kaheart [24]
You want to draw a free body diagram of the forces on the sled in the horizontal x-direction.

If you visualize the system in an x-y coordinate plane, the force along the x-direction is the angle it makes with the x-axis multiples by the force.

The angle made with the x-axis is cosine of the angle theta.

Please see picture attached.

5 0
3 years ago
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A marshmallow is dropped from a 5.71 meter high pedestrian bridge, and 0.921 seconds later, it lands right on the head of an uns
Natalka [10]

let the height of the person with marshmallow on her head be "h"

consider the motion of the marshmallow after it is dropped from bridge.

Y₀ = initial position of the marshmallow above the ground = 5.71 m

Y = final position of marshmallow on head of person = h

v₀ = initial velocity of the marshmallow = 0 m/s

a = acceleration due to gravity = - 9.8 m/s²

t = time of travel for marshmallow = 0.921 sec

Using the kinematics equation

Y = Y₀ + v₀ t + (0.5) a t²

inserting the values

h = 5.71 + 0 (0.921) + (0.5) (-9.8) (0.921)²

h = 5.71 - 4.16

h = 1.55 m

5 0
3 years ago
A 7.94-nC charge is located 1.77 m from a 4.14-nC point charge. (a) Find the magnitude of the electrostatic force that one charg
STatiana [176]

Answer:

F=94.32*10⁻⁹N  , The force F is repusilve because both charges have the same sign (+)

Explanation:

Two point charges (q₁, q₂) separated by a distance (d) exert a mutual force (F) whose magnitude is determined by the following formula:  

F=K*q₁*q₂/d² Formula (1)  

F: Electric force in Newtons (N)

K : Coulomb constant in N*m²/C²

q₁,q₂:Charges in Coulombs (C)  

d: distance between the charges in meters(m)

Equivalence  

1nC= 10⁻⁹C

Data

K=8.99x10⁹N*m²/C²

q₁ = 7.94-nC= 7.94*10⁻⁹C

q₂= 4.14-nC=  4.14 *10⁻⁹C

d= 1.77 m

Magnitude of the electrostatic force that one charge exerts on the other

We apply formula (1):

F=8.99x10^{9} *\frac{7.94*10^{-9} *4.14 *10^{-9} }{1.77^{2} }

F=94.32*10⁻⁹N  , The force F is repusilve because both charges have the same sign (+)

7 0
3 years ago
Akeem is walking on the beach on a hot summer day. The sand is very hot, so he runs and puts his feet in the water, which is muc
kramer

Sample Response: The water is cooler than the sand because it has a higher specific heat value. This means that it takes longer for the water to increase in temperature, making it feel cooler than the sand, which warms up more quickly.


4 0
3 years ago
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