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kirza4 [7]
4 years ago
14

What are the thee major wind systems

Physics
1 answer:
astra-53 [7]4 years ago
8 0
Trade winds, prevailing westerlies, polar easterlies
You might be interested in
Why are gases poor conductors of heat? A. Particles in a gas do not collide. B. Particles in a gas collide more often. C. Partic
german

Answer:

C. Particles in a gas collide less often.

5 0
3 years ago
5. A 1052 kg truck, starting from rest, reaches a speed of 20.0 m/s in 6.20 s.
BaLLatris [955]

Answer:

a. 3,392.7 N

b. 3,392.7 N

Explanation:

We are given the following information;

  • Mass of the truck as 1052 kg
  • initial speed as 0 m/s
  • Final speed as 20.0 m/s
  • Time taken as 6.20 s

#a. We are required to calculate the acceleration;

We need to know the formula of getting acceleration;

a = (v-u)/t

Where v is the final velocity, u is the initial velocity

Therefore;

a = (20 m/s - 0 m/s)/6.20s

= 3.225 m/s²

Thus, the average acceleration of the truck is 3.225 m/s²

#b. We are required to calculate the net force on the truck

We need to know that;

According to the second Newton's law of motion, F=ma

Where F is the net force, m is the mass and a is the acceleration.

Therefore;

Net force, F = mass × Acceleration

                    = 1052 kg × 3.225 m/s²

                    = 3,392.7 N

Thus, the net force on the truck is 3,392.7 N

4 0
4 years ago
A firecracker breaks up into two pieces , one has a mass of 200 g and files off along the x –axis with a speed of 82.0 m/s and t
Readme [11.4K]

Answer:

A) 21.2 kg.m/s at 39.5 degrees from the x-axis

Explanation:

Mass of the smaller piece = 200g = 200/1000 = 0.2 kg

Mass of the bigger piece = 300g = 300/1000 = 0.3 kg

Velocity of the small piece = 82 m/s

Velocity of the bigger piece = 45 m/s

Final momentum of smaller piece = 0.2 × 82 = 16.4 kg.m/s

Final momentum of bigger piece = 0.3 × 45 = 13.5 kg.m/s

since they acted at 90oc to each other (x and y axis) and also momentum is vector quantity; then we can use Pythagoras theorems

Resultant momentum² = 16.4² + 13.5² = 451.21

Resultant momentum = √451.21 = 21.2 kg.m/s at angle 39.5 degrees to the x-axis  ( tan^-1 (13.5 / 16.4)

5 0
3 years ago
Select the correct answer.
IgorC [24]

Answer:

D. Newton's Third Law of Motion

Explanation:

Newton's law of gravity is definitely not applicable to your hands. So we can cross this bad boy out

Newton's First Law is F=MA (force equals mass times acceleration). This is basically the root of most physics but it isn't the reason for your hand being red after hitting a wall.

Newton's Second law deals with velocities and forces, so even though you are apply a force your are not changing the velocity of the wall much.

Newton's Third Law basically says that for whatever force you apply to an object, that object will apply an equal and opposite force back to you. This is why your hand gets red. When you slap the wall with all your strength, the wall hits your hand back with the same amount of force. The 2nd law can also be seen when you're trying to push a desk and it won't budge. You are pushing on it, but the desk is pushing back. (there are multiple other factors applicable like friction but we physicists like to ignore them :) )

I hope this helps!

7 0
3 years ago
If a 10,000 g mass is suspended from a rope, what is the tensile force in the rope?
nadezda [96]

To solve this problem we will apply Newton's second law and the principle of balancing Forces on the rope. Newton's second law allows us to define the weight of the mass, through the function

F = ma\rightarrow F =mg

Here,

m = mass

a = g = Gravitational acceleration

Replacing we have that the weight is

W= (10kg)(9.8)

W = 98N

Since the rope is taut and does not break, the net force on the rope will be zero.

\sum F = 0

T-W = 0

T = W

T = 98N

Therefore the tensile force in the rope is 98N

8 0
3 years ago
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