Answer: The ball would have the most kinetic energy at the lowest point and the most potential energy at the top of the hill
Explanation:
Since you didnt add the picture I cant tell which multiple choice answer it would be, but I hope this helps :)
Answer:
Newton/meter
Explanation:
Acceleration is defined as the rate of change of velocity.
Therefore, the SI units of acceleration is m/sec²
However, acceleration is also involved in Newton's second law:
Force = mass * acceleration
Newton = kg * unit of acceleration
Therefre:
unit of acceleration = Newton / kg
Hope this helps :)
The existence of atmosphere increases the average planetary temperature by more than 15°C, due to the greenhouse effect of some atmospheric compounds. The most important of them are water vapour (H2O), ozone (O3), carbon dioxide (CO2), and methane (CH4).
Complete Question
An athlete at the gym holds a 3.0 kg steel ball in his hand. His arm is 70 cm long and has a mass of 4.0 kg. Assume, a bit unrealistically, that the athlete's arm is uniform.
What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor? Include the torque due to the steel ball, as well as the torque due to the arm's weight.
Answer:
The torque is ![\tau = 34.3 \ N\cdot m](https://tex.z-dn.net/?f=%5Ctau%20%3D%2034.3%20%5C%20%20N%5Ccdot%20m)
Explanation:
From the question we are told that
The mass of the steel ball is ![m = 3.0 \ kg](https://tex.z-dn.net/?f=m%20%20%3D%20%203.0%20%5C%20%20kg)
The length of arm is ![l = 70 \ cm = 0.7 \ m](https://tex.z-dn.net/?f=l%20%3D%20%2070%20%5C%20cm%20%20%3D%200.7%20%5C%20%20m)
The mass of the arm is ![m_a = 4.0 \ kg](https://tex.z-dn.net/?f=m_a%20%20%3D%204.0%20%5C%20%20kg)
Given that the arm of the athlete is uniform them the distance from the shoulder to the center of gravity of the arm is mathematically represented as
![r = \frac{l}{2}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7Bl%7D%7B2%7D)
=>
=>
Generally the magnitude of torque about the athlete shoulder is mathematically represented as
![\tau = m_a * g * r + m * g * L](https://tex.z-dn.net/?f=%5Ctau%20%3D%20%20m_a%20%2A%20g%20%2A%20r%20%20%2B%20m%20%2A%20g%20%2A%20%20L)
=> ![\tau = 4 * 9.8 * 0.35 + 3 * 9.8 * 0.70](https://tex.z-dn.net/?f=%5Ctau%20%3D%20%204%20%2A%209.8%20%2A%200.35%20%2B%203%20%2A%209.8%20%2A%20%200.70)
=> ![\tau = 34.3 \ N\cdot m](https://tex.z-dn.net/?f=%5Ctau%20%3D%2034.3%20%5C%20%20N%5Ccdot%20m)