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3 years ago

Whats the answer to 10a² - 6ab + 10 -2a² - 4ab +15b?

Physics

1 answer:

Angelina_Jolie [31]3 years ago

8 0

8a2-10ab+15b+10 Explaintion:

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A car accelerates from rest at 3.00 m/second squared What is the velocity after 5 secs ? What is the displacement after 5 second

andrey2020 [161]

Explanation:

after 5 seconds, the velocity is (5s)(3m/s²) = 15m/s

The displacement after 5s is

x=vo + (1/2)at²

x = 0 + (1/2)(3m/s²)(5s)(5s)

x= 37.5 m

3 0

3 years ago

A cyclist going downhill is accelerating at 1. 2 m/s2. If the final velocity of the cyclist is 16 m/s after 10 seconds, what is

mel-nik [20]

Answer:

$\boxed {\boxed {\sf v_i= 4 \ m/s}}$

Explanation:

We are asked to find the cyclist's initial velocity. We are given the acceleration, final velocity, and time, so we will use the following kinematic equation.

$v_f= v_i + at$

The cyclist is acceleration at 1.2 meters per second squared. After 10 seconds, the velocity is 16 meters per second.

$v_f$ = 16 m/s
a= 1.2 m/s²
t= 10 s

Substitute the values into the formula.

$16 \ m/s = v_i + (1.2 \ m/s^2)(10 \ s)$

Multiply.

$16 \ m/s = v_i + (1.2 \ m/s^2 * 10 \ s)$

$16 \ m/s = v_i + 12 \ m/s$

We are solving for the initial velocity, so we must isolate the variable $v_i$ . Subtract 12 meters per second from both sides of the equation.

$16 \ m/s - 12 \ m/s = v_i + 12 \ m/s -12 \ m/s$

$4 \ m/s = v_i$

The cyclist's initial velocity is <u>4 meters per second.</u>

6 0

3 years ago

Just want a ride with

yaroslaw [1]

Answer:

My best friend lol cuz since quarantine i didn't see her

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3 years ago

This diagram shows how a certain type of precipitation is formed. Water drops are caught in up-drafts and down-drafts, over and

Svet_ta [14]

It would be B. Hail.

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4 years ago

An iron railroad rail is 700 ft long when the temperature is 30°C. What is its length when the temperature is – 10°C?

MAVERICK [17]

Answer:

699.67ft

Explanation:

We are given with,

α = 1.2×10⁻⁵ / °C
L₀ = 700 ft
ΔT = -10°C − 30°C = -40°C

Now, We have to find ΔL:

ΔL = (1.2×10⁻⁵ / °C) (700 ft) (-40°C)
ΔL = −0.336

Rounded to two significant figures, the change in length is −0.33ft.

<u>Therefore, the final length is approximately 700 ft − 0.33 ft = 699.67ft</u>.

6 0

3 years ago

Whats the answer to 10a² - 6ab + 10 -2a² - 4ab +15b?​

Whats the answer to 10a² - 6ab + 10 -2a² - 4ab +15b?