Whats the answer to 10a² - 6ab + 10 -2a²

The heat capacity of 0.125Kg of water is measured to be 523j/k at a room temperature.Hence, calculate the heat capacity of water

Naily [24]

Answer:

A. 4148 J/K/Kg

B. 4148 J/K/L

Explanation:

A. Heat capacity per unit mass is known as the specific heat capacity, c.

C = Heat capacity/mass(kg)

C = (523 J/K) / 0.125 Kg = 4148 J/K/Kg

B. Volume of water = mass/density

Density of water = 1 Kg/L

Volume of water = 0.125 Kg/ 1Kg/L

Volume of water = 0.125 L

Heat capacity per unit volume = (523 J/K) / 0.125 L

Heat capacity per unit volume = 4148 J/K/L

5 0

2 years ago

Pls help i’ll give brainliest if you give a correct answer!!

enot [183]

Answer:

the second one

Explanation:

4 0

2 years ago

A ball is thrown horizontally from the top of a tall cliff. Neglecting air drag, what vertical distance will the ball have falle

adell [148]

The relevant equation to use here is:

y = v0 t + 0.5 g t^2

where y is the vertical distance, v0 is initial velocity = 0, t is time, g = 9.8 m/s^2

y = 0 + 0.5 * 9.8 * 3^2

<span>y = 44.1 meters</span>

5 0

3 years ago

The rate (in mg carbon/m3/h) at which photosynthesis takes place for a species of phytoplankton is modeled by the function P = 9

Ivanshal [37]

Answer:

At light intensity I = 3, is P a maximum

Explanation:

Given:

$P=\frac{90I}{I^2+I+9}$

now differentiating the above equation with respect to Intensity 'I' we get

$\frac{dp}{dI}=\frac{(I^2+I+9).\frac{d(90I)}{dI}-90I.\frac{d((I^2+I+9)}{dI}}{(I^2+I+9)^2}$

or

$\frac{dp}{dI}=\frac{(I^2+I+9).90-90I.(2I+1)}{(I^2+I+9)^2}$

or

$\frac{dp}{dI}=\frac{90I^2+90I+810)-(180I^2+90I)}{(I^2+I+9)^2}$

or

$\frac{dp}{dI}=\frac{-90I^2+810)}{(I^2+I+9)^2}$

Now for the maxima $\frac{dP}{dI}=0$

thus,

$0=\frac{-90I^2+810)}{(I^2+I+9)^2}$

or

$-90I^2+810=0$

or

$I^2=\frac{810}{90}$

or

$I^2=9$

or

I = 3

thus, <u>for the value of intensity I = 3, the P is maximum</u>

at I = 3

$P=\frac{90\times3}{3^2+3+9}$

or

$P=\frac{270}{21}$

or

$P=12.85$

5 0

3 years ago

NEED ANSWERED ASAP!! will give brainliest!

kotegsom [21]

The kinetic energy of any moving object is

K.E. = (1/2) (mass) (speed)² .

To use this simple formula, the 'mass' has to be in kilograms,
and the 'speed' has to be in meters-per-second.

You can see that we have a slight problem that has to be cleaned up:
The speed in the question is given in "kilometers per hour", but we'll
need it in "meters per second". So let's convert that right now:

(600 km/hour) x (1 hour / 3600 seconds) x (1000 meters / km)

= (600 x 1 x 1000 / 3600) (km-hour-meters / hour-second-km)

= 166.67 meters/second .

Now we're ready to plug numbers into the formula for K.E.

(1/2) (mass) (speed)²

= (1/2) (80,000 kg) (166.67 m/s)²

= (40,000 kg) (27,777.8 m²/s²)

= 1,111,111,111 kg-m²/s²

= 1.1... x 10⁹ Joules (choice D)

8 0

2 years ago

Whats the answer to 10a² - 6ab + 10 -2a² - 4ab +15b?​

Whats the answer to 10a² - 6ab + 10 -2a² - 4ab +15b?