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bazaltina [42]
3 years ago
11

What will most likely happen if a light wave moves through a solid?

Physics
2 answers:
Kazeer [188]3 years ago
8 0
In will most likely decrease its speed.
hope this helps.
Norma-Jean [14]3 years ago
8 0

<u>Answer:</u> the correct answer is it will decrease in speed.

<u>Explanation:</u>

There are 2 types of waves:

1. Longitudinal waves: These waves are the waves where the particles of the medium propagates in the direction of the wave. These waves requires a medium to travel. For Example: Sound Waves.

2. Transverse wave: These waves are the waves where the particles of the medium propagates perpendicular to the direction of the wave. These waves does not require a medium to travel. They can travel in vacuum also. For Example: Light waves.

Speed of light wave is constant in the vacuum which is 3\times 10^8m/s but its speed decreases as it enters a medium. And, here the light is entering a solid having certain refractive index, so the speed would decrease.

Hence, the correct answer is it will decrease in speed.

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4 0
3 years ago
A motorcycle has 100,000 J of kinetic energy and is traveling at 20 m/s. Find its mass.
tankabanditka [31]

Answer:

<h3>The answer is 500 kg</h3>

Explanation:

The mass of the object can be found by using the formula

m =  \frac{2KE}{ {v}^{2} }  \\

v is the velocity

KE is the kinetic energy

From the question we have

m =  \frac{2 \times 100000}{  {20}^{2}  }  =  \frac{200000 }{400} =   \frac{2000}{4}  \\

We have the final answer as

<h3>500 kg</h3>

Hope this helps you

7 0
3 years ago
A uniformly charged solid disk of radius R = 0.45 m carries a uniform charge density of σ = 175 μC/m². A point P is located a di
siniylev [52]

Answer:

1408.685 KN/C

Explanation:

Given:

R = 0.45 m

σ = 175 μC/m²

P is located a distance a = 0.75 m

k = 8.99*10^9

  • The Electric Field Strength E of a uniformly solid disk of charge at distance a perpendicular to disk is given by:

                                  E = 2*pi*k*o * (1 - \frac{a}{\sqrt{a^2 + R^2} })\\

part a)

Electric Field strength at point P: a = 0.75 m

E = 2*pi*8.99*10^9*175*10^-6 * (1 - \frac{0.75}{\sqrt{0.75^2 + 0.45^2} })\\\\E = 9885021.285*(0.1425070743)\\\\E = 1408.685 KN/C

part b)

Since, R >> a, we can approximate a / R = 0 ,

Hence, E simplified relation becomes:

E = 2*pi*k*o * (1 - \frac{a/R}{\sqrt{a^2/R^2 + 1} })\\\\E = 2*pi*k*o * (1 - \frac{0}{\sqrt{0 + 1} })\\\\E = 2*pi*k*o

E = σ / 2*e_o

part c)

Since, a >> R, we can approximate. that the uniform disc of charge becomes a single point charge:

Electric Field strength due to point charge is:

E = k*δ*pi*R^2 / a^2  

Since, R << a, Surface area = δ*pi

Hence,

E = (k*δ*pi/a^2)

 

6 0
3 years ago
In the history of astronomy, which of the following is true? . A] Tycho Brahe built one of the first observatories. B] Ptolemy w
Gelneren [198K]
D. <span>Johannes Kepler argued that Earth was the center of the universe.

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4 0
3 years ago
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A 10000 N net force is accelerating a car at a rate if 5.5 m/s^2. What is the cars’s mass?
lianna [129]

Answer:

1800 kg

Explanation:

Newton's second law:

F = ma

10000 N = m (5.5 m/s²)

m ≈ 1800 kg

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3 years ago
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