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3 years ago

What will most likely happen if a light wave moves through a solid?

Physics

2 answers:

Kazeer [188]3 years ago

8 0

In will most likely decrease its speed.
hope this helps.

Norma-Jean [14]3 years ago

8 0

<u>Answer:</u> the correct answer is it will decrease in speed.

<u>Explanation:</u>

There are 2 types of waves:

1. Longitudinal waves: These waves are the waves where the particles of the medium propagates in the direction of the wave. These waves requires a medium to travel. For Example: Sound Waves.

2. Transverse wave: These waves are the waves where the particles of the medium propagates perpendicular to the direction of the wave. These waves does not require a medium to travel. They can travel in vacuum also. For Example: Light waves.

Speed of light wave is constant in the vacuum which is $3\times 10^8m/s$ but its speed decreases as it enters a medium. And, here the light is entering a solid having certain refractive index, so the speed would decrease.

Hence, the correct answer is it will decrease in speed.

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A coil formed by wrapping 65 turns of wire in the shape of a square is positioned in a magnetic field so that the normal to the

Fiesta28 [93]

Answer:

377 m

Explanation:

number of turns, N = 65

θ = 36°

B1 = 200 micro Tesla

B2 = 600 micro tesla

t = 0.4 s

induced emf, e = 80 mV

Let a be the side of the square coil.

$e=\frac{d\phi }{dt}=NA\frac{dB}{dt}\times Sinθ$

$0.080=\frac{65\times a^{2}\times Sin36\times\left ( 600 - 200 \right )\times 10^{-6}}{0.4}$

$0.080=0.038a^{2}$

a = 1.45 m

Total length of the wire, L = N x 4a = 65 x 4 x 1.45 = 377 m

Thus, the length of the wire is 377 m.

7 0

3 years ago

All stars go through a lifecycle.

Komok [63]

Mira is much bigger than the Sun.

Only very massive stars will go through a supernova stage, causing the outer layer to explode away and the core to collapse in on itself, becoming very dense.

5 0

2 years ago

Read 2 more answers

I attach a 4.1 kg block to a spring that obeys Hooke's law and supply 3.8 J of energy to stretch the spring. I release the block

borishaifa [10]

Answer:

The amplitude of the oscillation is 2.82 cm

Explanation:

Given;

mass of attached block, m = 4.1 kg

energy of the stretched spring, E = 3.8 J

period of oscillation, T = 0.13 s

First, determine the spring constant, k;

$T = 2\pi \sqrt{\frac{m}{k} }$

where;

T is the period oscillation

m is mass of the spring

k is the spring constant

$T = 2\pi \sqrt{\frac{m}{k} } \\\\k = \frac{m*4\pi ^2}{T^2} \\\\k = \frac{4.1*4*(3.142^2)}{(0.13^2)} \\\\k = 9580.088 \ N/m\\\\$

Now, determine the amplitude of oscillation, A;

$E = \frac{1}{2} kA^2$

where;

E is the energy of the spring

k is the spring constant

A is the amplitude of the oscillation

$E = \frac{1}{2} kA^2\\\\2E = kA^2\\\\A^2 = \frac{2E}{k} \\\\A = \sqrt{\frac{2E}{k} } \\\\A = \sqrt{\frac{2*3.8}{9580.088} }\\\\A = 0.0282 \ m\\\\A = 2.82 \ cm$

Therefore, the amplitude of the oscillation is 2.82 cm

8 0

3 years ago

The stars in the sky are organized into groups of stars called constellations which appear near each other in the sky but are no

bezimeni [28]

Answer:

The International Astronomical Union (IAU) has accepted 88 constellations in the sky.

Explanation:

Constellations has been used since the beginnings of civilizations and each one of them named them as they considered appropiate. It means Greeks' constellations were different than the ones described by Chinese, so it was necessary to gather all these constellations and make a great record with all of them, but there was a problem: Some constellations from different civilizations overlaped because they shared the same stars. There was necessary to put some order on this and that is when in 1922 the International Astronomical Union (IAU) defned a set of 88 moderm constellations that would become the international standard to look at the night sky. Each one of them is unique and does not share stars with the other constellations.

6 0

3 years ago

Can someone please help with this problem?

andriy [413]

no question please so what's the problem

4 0

3 years ago