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bazaltina [42]
4 years ago
11

What will most likely happen if a light wave moves through a solid?

Physics
2 answers:
Kazeer [188]4 years ago
8 0
In will most likely decrease its speed.
hope this helps.
Norma-Jean [14]4 years ago
8 0

<u>Answer:</u> the correct answer is it will decrease in speed.

<u>Explanation:</u>

There are 2 types of waves:

1. Longitudinal waves: These waves are the waves where the particles of the medium propagates in the direction of the wave. These waves requires a medium to travel. For Example: Sound Waves.

2. Transverse wave: These waves are the waves where the particles of the medium propagates perpendicular to the direction of the wave. These waves does not require a medium to travel. They can travel in vacuum also. For Example: Light waves.

Speed of light wave is constant in the vacuum which is 3\times 10^8m/s but its speed decreases as it enters a medium. And, here the light is entering a solid having certain refractive index, so the speed would decrease.

Hence, the correct answer is it will decrease in speed.

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1. Which of the following causes physical erosion?
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The momentum of a 5-kilogram object moving at 6 meters per second is-
goldfiish [28.3K]
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3 0
3 years ago
A 645 g block is released from rest at height h0 above a vertical spring with spring constant k = 530 N/m and negligible mass. T
Nina [5.8K]

Answer:

a)5.88J

b)-5.88J

c)0.78m

d)0.24m

Explanation:

a) W by the block on spring is given by

W= \frac{1}{2}kx² = \frac{1}{2}(530)(0.149)² =  5.88 J

b)  Workdone by the spring = - Workdone by the block = -5.88J

c) Taking x = 0 at the contact point we have U top = U bottom

So, mgh_o = \frac{1}{2}kx² - mgx

And, h_o= ( \frac{1}{2}kx² - mgx )/(mg) = [\frac{1}{2} (530)(0.149^2)-(0.645)(9.8)(0.149)]/(0.645x9.8)    

   h_o=   0.78m            

d) Now, if the initial initial height of block is 3h_o

h_o = 3 x 0.78 = 2.34m

then, \frac{1}{2}kx² - mgx - mgh_o =0

 

\frac{1}{2}(530)x²  - [(0.645)(9.8)x] - [(0.645)(9.8)(2.34) = 0

265x² - 6.321x - 14.8 = 0  

a=265

b=-6.321

c=-14.8

By using quadratic eq. formula, we'll have the roots

x= 0.24 or x=-0.225

Considering only positive root:

x= 0.24m (maximum  compression of the spring)

4 0
3 years ago
A fisherman has caught a very large, 5.0 kg fish from a dock that is 2.0 m above the water. He is using lightweight fishing line
sergeinik [125]

Answer:

The least amount of time in which the fisherman can raise the fish to the  dock without losing it is t= 2 seconds.

Explanation:

m= 5 kg

h= 2m

Fmax= 54 N

g= 9.8 m/s²

W= m * g

W= 49 N

F= Fmax - W

F= 5 N

F=m*a

a= F/m

a= 1 m/s²

h= a * t²/2

t= √(2*h/a)

t= 2 seconds

6 0
3 years ago
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