Question

Consider the function represented by the equation 6q = 3s - 9. Write the equation in function notation, where q is the independent variable.

Answer 1

Basically they want you to solve for q
6q=3s-9
divide both sides by 6
q=1/2s-3/2

Answer 2

Answer:

Given the equation:

$6q = 3s -9$

Add 9 to both sides we have;

$6q+9= 3s -9+9$

Simplify:

$6q+9= 3s$

Divide by 3 to both sides we have;

$\frac{1}{3}(6q+9)=s$

Using the distributive property, $a \cdot (b+c) = a\cdot b+ a\cdot c$

$2q+3 = s$

or

$s = 2q+3$ where,  q is independent variable and s is the dependent variable.

Use notation: s = f(q)

Therefore, the equation in function notation:

$f(q) = 2q+3$, where q is the independent variable