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sergejj [24]
3 years ago
5

The image above was taken by the spacecraft Messenger as it flew by the planet Mercury. The terrain shown in this image is typic

al for the surface of Mercury. There are many circular depressions of various sizes in the scene (the largest one in the upper right part of the image is about 133 km across). These depressions are called _______ and formed when asteroids and comets struck the planet.
A.
volcanoes
B.
mountain ranges
C.
tectonic plates
D.
impact craters
Physics
1 answer:
lorasvet [3.4K]3 years ago
7 0
The answer is

C


Hope this helps
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Olaf is standing on a sheet of ice that covers the football stadium parking lot in Buffalo, New York; there is negligible fricti
Bas_tet [7]

Answer:

v = 0.059 m/s

Explanation:

To find the final speed of Olaf and the ball you use the conservation momentum law. The momentum of Olaf and the ball before catches the ball is the same of the momentum of Olaf and the ball after. Then, you have:

mv_{1i}+Mv_{2i}=(m+M)v  (1)

m: mass of the ball = 0.400kg

M: mass of Olaf = 75.0 kg

v1i: initial velocity of the ball = 11.3m/s

v2i: initial velocity of Olaf = 0m/s

v: final velocity of Olaf and the ball

You solve the equation (1) for v and replace the values of all variables:

v=\frac{mv_{1i}}{m+M}=\frac{(0.400kg)(11.3m/s)}{0.400kg+75.0kg}=0.059\frac{m}{s}

Hence, after Olaf catches the ball, the velocity of Olaf and the ball is 0.059m/s

3 0
3 years ago
Where is most of the energy from incoming waves focused?
zavuch27 [327]
I'd say B since headland since whenever there's a crash wave, headland receives most of the impact
3 0
3 years ago
PLS HELP ASAP (no links)
nikklg [1K]

Answer:

The mass goes down

Explanation:

Because mass is the quantity of matter contained in a substance And Volume is the space occupied by a substance. So when the volume is less the mass decreases

6 0
3 years ago
Read 2 more answers
A vehicle moving with a uniform a acceleration of 2m/s and has a velocity of 4m/s at a certain time .
Evgesh-ka [11]

Answer:

1 second later the vehicle's velocity will be:

v(1)= 6\,\,\frac{m}{s} \\

5 seconds later the vehicle's velocity will be:

v(5)=14\,\,\frac{m}{s}

Explanation:

Recall the formula for the velocity of an object under constant accelerated motion (with acceleration "a"):

v(t)=v_0+a\,t

Therefore, in this case v_0=4\,\,\frac{m}{s}  and a=2\,\,\frac{m}{s^2}

so we can estimate the velocity of the vehicle at different times just by replacing the requested "t" in the expression:

v(t)=v_0+a\,t\\v(t)=4+2\,\,t\\v(1)=4+2\,(1) = 6\,\,\frac{m}{s} \\v(5)=4+2\,(5)=14\,\,\frac{m}{s}

3 0
3 years ago
John bounces a ball off the ground, and it leaves the ground with a velocity of 10 m/s. How long will it take the ball to reach
Maksim231197 [3]

Explanation:

This is true because at maximum height, the velocity is 0

8 0
3 years ago
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