there are 8 pencils in a package. how many packages will be needed for 28 children if each child gets 4 pencils

Braden has 3 soccer balls and 2 basketballs that weighs a total of 5.44 pounds. Which equation and solution can be used to deter

STALIN [3.7K]

3x+2y=5.44
it's a two variable problem which can't be solved algebraically unless you are given the weight of one of the balls.

8 0

3 years ago

The length of a rectangle is twice it’s width if the perimeter of the rectangle is 60 yards find its length and width

grandymaker [24]

Length =20
width =10

6 0

4 years ago

Find the rate of change

Arte-miy333 [17]

Answer:

2

Step-by-step explanation:

the rate of change is Rise/ Run

= Δy / Δx

= (y2 – y1) / (x2 – x1)

= (1 - (-1))/(-1 - (-2))

=2/1

=2

7 0

3 years ago

The time (in minutes) required to learn the procedure for performing a certain task is uniformly distributed on the interval fro

PtichkaEL [24]

Answer:

a

$P( X > 46) = 0.7 \ minute$

b

$\mu = 42 \ minute$

Step-by-step explanation:

From the question we are told that

The procedure for performing a certain task is uniformly distributed on the interval from( a = 32 )minutes to (b= 52) minutes

Generally the cumulative distribution function for continuous uniform distribution is

$F(x) = \left \{ {{0 \ \ \ \ \ for \ x \ x < a} \atop {\frac{x-a}{b-a} } \ \ for \ a \le x \ge b} \atop {1 \ \ \ \ \ \ \ for \ x > b }\right.$

Generally the probability that it takes more than 46 minutes to learn the procedure is mathematically represented as

$P( X > 46) = F(46) = \frac{46 - 32}{52-32}$

=> $P( X > 46) = 0.7 \ minute$

Generally the average time required to learn the procedure is mathematically represented as

$\mu = \frac{a + b}{2}$

=> $\mu = \frac{32 + 52}{2}$

=> $\mu = 42 \ minute$

3 0

3 years ago

Select the correct augmented matrices. Liam wants to buy a car and pay for it in three installments. The total cost of the car i

Alexxandr [17]

Answer:

Step-by-step explanation:

Given:

The total cost of the car is 29,000 dollars. Which is paid in three installments . x , y and z are the installments.

To Find:

The value of x, y and z.

Solving:

It is said that 2 times the 1 installment is $1,000 ore than the sum of the 3 rd installment and 3 times the second installment.

= 2x = 1000 + z + 3y

Transposing:

= z = 2x - 3y - 1000

x + y + z = 29000 + 2100

= x + y + z = 31100

= x + y + 2x - 3y - 1000 = 31100

= 3x - 2y = 32100

First installment at start paid = x (We have assumed)

Remaining Installment which is left to pay = 29,000 - x

(29,000 - x) * 15 /100 = Interest for First

= (29000 - x) * 3/20

=> 4350 - 0.15x

Installment Paid Second = y

(29000 - x) + 4350 - 0.15x - y ) * 15/100 = Interest Second

(29000 - x) + 4350 - 0.15x - y ) * 3/20

= 5002.5 - 0.1725x - 0.15y

Interest of 1st installment + Interest of 2nd installment = 2100

Using this principle solving:

= 4,350 - 0.15x + 5,002.5 - 0.1725x - 0.15y = 2,100

= 0.3225x + 0.15y = 7,252.5

= 6.45x + 3y = 1,45,050

= 12.9x + 6y = 2,90,100

= 4.3x + 2y = 96,700

= 4.3x + 2y = 96700

= 3x - 2y = 32,100

= 7.3x = 1,28,800

= x ≈ 17644 ( 17,643.8356)

3x - 2y = 32,100

= y ≈ 10416 (10,415.7534 )

x + y + z = 31100

= z ≈ 3040 ( 3,040.4110 )

7 0

4 years ago