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3 years ago

In the chemical formula 3nh3, how many atoms of hydrogen (h) are there? 3 6 9 11

Chemistry

2 answers:

ANTONII [103]3 years ago

7 0

Your answer is 3! Hope you get a good grade :)♥

Sergeeva-Olga [200]3 years ago

5 0

Answer: There are 9 hydrogen atoms in the given chemical formula.

Explanation:

We are given a chemical formula of ammonia which is $NH_3$

This molecule is formed by the combination of hydrogen and nitrogen atoms.

In 1 mole of ammonia, 1 atom of nitrogen is there and 3 atoms of hydrogen is there.

We are given:

Moles of ammonia = 3

So, 3 atoms of nitrogen is there and 9 atoms of hydrogen is there.

Hence, there are 9 hydrogen atoms in the given chemical formula.

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How to tell which element is oxidized in a reaction?

adoni [48]

If in a redox reaction oxidation state of elements decreases or looses electron(s), the element is said to be oxidized. Hope this helps you!

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3 years ago

Which describes radioactive decay of a substance? More of the radioactivity is lost during the first half-life than in later hal

vovangra [49]

Answer:More of the radioactivity is lost during the first half-life than in later half-lives.

Explanation: Passed test with 98

5 0

3 years ago

Read 2 more answers

The prevailing atmospheric pressure on a plateau in Colorado is 0.706 atm. Express this pressure in pounds per square inch, kilo

noname [10]

Answer:

1. 10.37114 psi

2. 71.5178 KPa

3. 71517.8 Pa

4. 536.56 mmHg.

5. 21.12352 inHg

Explanation:

From the question given,

Pressure = 0.706 atm

The pressure in other units of measurement is obtained as follow:

1. Pressure in Psi

1 atm = 14.69 psi

Therefore, 0.706 atm = 0.706 x 14.69 = 10.37 psi

2. Pressure in KPa

1 atm = 101.3 kPa

Therefore, 0.706 atm = 0.706 x 101.3 = 71.5178 KPa

3. Pressure in Pa

1 atm = 1.013x10^5 Pa

Therefore, 0.706 atm = 0.706 x 1.013x10^5 = 71517.8 Pa

4. Pressure in mmHg

1 atm = 760mmHg

Therefore, 0.706 atm = 0.706 x 760 = 536.56 mmHg

5. Pressure in inHg

1 atm = 29.92 inHg

Therefore, 0.706 atm = 0.706 x 29.92 = 21.12352 inHg

5 0

3 years ago

Please help ASAP!!!

umka2103 [35]

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I have gotten these answers checked and they are right.

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3 years ago

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What is the empirical formula of a compound with a percent composition of 22.5% Phosphorous and 77.5% Chlorine?

sashaice [31]

Answer:

$\boxed {\boxed {\sf PCl_3}}$

Explanation:

We are given the percent composition: 22.5% phosphorus and 77.5% chlorine.

We can assume there are 100 grams of this compound. We choose 100 because we can simply use the percentages as the masses.

22.5 g P
77.5 g Cl

Next, convert these masses to moles, using the molar masses found on the Periodic Table.

P: 30.974 g/mol
Cl: 35.45 g/mol

Use the molar masses as ratios and multiply by the number of grams. $22.5 \ g \ P * \frac {1 \ mol \ P }{30.974 \ g \ P}= \frac {22.5 \ mol \ P }{ 30.974} = 0.7264157035 \ mol \ P$

$77.5 \ g \ Cl * \frac {1 \ mol \ Cl }{35.45 \ g \ Cl}= \frac {77.5 \ mol \ Cl }{ 35.45} \ =2.186177715 \ mol \ Cl$

Divide both of the moles by the smallest number of moles to find the mole ratio.

$\frac {0.7264157035} {0.7264157035} = 1$

$\frac {2.186177715}{0.7264157035}=3.009540824 \approx 3$

The mole ratio is about 1 P: 3 Cl, so the empirical formula is written as: PCl₃

4 0

2 years ago