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2 years ago

A 55.0 g aluminum block initially at 27.5 ∘c absorbs 725 j of heat. what is the final temperature of the aluminum?

Chemistry

1 answer:

Airida [17]2 years ago

8 0

Final temperature of the aluminum is 41.8 °C

We have the equation for energy

E = mc∆T

Here m = 55 g = 0.055 kg

∆T=T-27.5

Specific heat capacity of aluminum = 921.096 J/kg.K

E = 725 J

Substituting

E = mc∆T

725 0.055 x 921.096 x (T - 27.5)

T-27.5 14.31

T=41.81° C = 41.8 °C

41.8 °C

Final temperature of the aluminum = 41.8°C

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3 years ago

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3 years ago

Guillaume Amontons first took a stab at measuring absolute zero in 1702. What would be the most reasonable way it would have bee

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The most reasonable way to measure absolute zero would have been to extrapolate the ideal gas law.

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3 0

2 years ago

When 5.0 mol Al react with 13 mol HCl, what is the limiting reactant, and how many moles of AlCl3 can be formed? (2 points) 2Al

barxatty [35]

Well, we need to find the ratio of Al to the other reactant.

Al:HCl = 1:3

--> this means that for every 1 Al used, you have to use 3 HCl.

5*3 = 15 moles of HCl needed to fully react with 5 moles of Al. Since 13<15, HCL is the limiting reactant.

The ratio of HCl:AlCl = 3:1

13/3 = 4.3333...

The final answer is HCl is the limiting reactant with 4.3 moles of AlCl3 able to be produced so choice B.

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4 years ago