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kow [346]
3 years ago
9

Which describes radioactive decay of a substance? More of the radioactivity is lost during the first half-life than in later hal

f-lives. More of the radioactivity is lost during the fourth half-life than in the first half-life. Isotopes are the most stable during the first half-life. Isotopes are the least stable during the later half-lives.
Chemistry
2 answers:
Alja [10]3 years ago
8 0

Answer:

Yes, A.) "More of the radioactivity is lost during the first half-life than in later half-lives."  is the correct answer!!

Explanation:

I took the practice test on edge

vovangra [49]3 years ago
5 0

Answer:More of the radioactivity is lost during the first half-life than in later half-lives.

Explanation: Passed test with 98

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At the end of the reaction, the catalyst is UNCHANGED.
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How does changing the concentration of the reactants change the parts of a rate law? It changes the rate, R. It changes the rate
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Answer

A. It changes the rate, R

Explanation

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How much heat does it take to turn water from -30 degreesC to 120 degreesC?
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Free-energy change, ΔG∘, is related to cell potential, E∘, by the equationΔG∘=−nFE∘where n is the number of moles of electrons t
mart [117]

Answer:

a)\Delta G=372490 J

b)\Delta G=-568614 J

Explanation:

a) The reaction:

Mg(s) +Fe^{2+}(aq) \longrightarrow Mg^{2+}(aq) + Fe(s)

The free-energy expression:

\Delta G=-n*F*E

E=E_{red}-E_{ox]

The element wich is reduced is the Fe and the one that oxidates is the Mg:

-0.44V=E_{red}-(-2.37V)=1.93V

The electrons transfered (n) in this reaction are 2, so:

\Delta G=-2mol*96500 C/mol * 1.93 V

\Delta G=-372490 J

b) If you have values of enthalpy and enthropy you can calculate the free-energy by:

\Delta G=\Delta H - T* \Delta S

with T in Kelvin

\Delta G=-675 kJ*\frac{1000J}{kJ} - 298K*-357 J/K

\Delta G=-568614 J

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3 years ago
Is the center of an atom is called the nucleus?​
Nuetrik [128]

Answer:

The center of the atom contains the nucleus so yes

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