Answer:
Light reaction do not depends on dark reaction because the reaction that occur in presence of light cannot occur in dark . Photolysis, one of most important light reaction cannot take place in dark.
Explanation:
If concentration of carbon dioxide is decreased by 50% then the oxygen production will not be affected because oxygen is produced from the reduction of water.
<u>Given:</u>
H2(g) + Cl2 (g) → 2HCl (g)
<u>To determine:</u>
The enthalpy of the reaction and whether it is endo or exothermic
<u>Explanation:</u>
Enthalpy of a reaction is given by the difference between the enthalpy of formation of reactants and products
ΔH = ∑nHf (products) - ∑nHf (reactants)
= [2Hf(HCl)] - [Hf(H2) + Hf(Cl2)] = 2 (-92.3) kJ = - 184.6 kJ
Since the reaction enthalpy is negative, the reaction is exothermic
<u>Ans:</u> The enthalpy of reaction is -184. kJ and the reaction is exothermic
Answer:
Explanation:
so u can work out the amount of moles of S8 by using
moles=mass/mr
=16/32.1=0.498moles
then use the molar ratio of
S : Fe
1:1 so the moles of Fe is the same 0.498
The use the equation
mass = mr x moles
=55.8 x 0.498
=27.78
so 27.8 g
hope this make sense :)
2HF + Na2SiO3 ----> 2NaF + H2SiO3 is the balanced equation.
2 moles of HF form 2 moles of NaF
therefore 0.508 Mol HF forms 0.508 mol of NaF
In grams this is 0.508( rel atomic mass of Na + RAM of F)
= 0.508 (22.99+19)
= 21.33 grams
Answer:
a) 7.0 moles of NH3
b) 61.2 g of NH3
c) 4.15 g of H2
d) 8.9 ×10^19 molecules
Explanation:
Equation of the reaction;
N2(g) + 3H2(g) ⇄NH3(g)
a)
If 3 moles of H2 yields 1 mole of NH3
21 moles of H2 will yield 21 × 1 /3 = 7.0 moles of NH3
b)
1 mole of N2 yields 17 g of NH3
3.6 moles of N2 yields 3.6 moles × 17 g of NH3 = 61.2 g of NH3
c)
If 6g of H2 produces 17 g of NH3
xg of H2 will produce 11.76 g of NH3
x= 6 × 11.76/17
x= 4.15 g of H2
d)
If 6g of hydrogen yields 6.02 × 10^23 molecules of NH3
8.86 × 10^-4g of H2 yields 8.86 × 10^-4g × 6.02 × 10^23 /6 = 8.9 ×10^19 molecules
