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3 years ago

Which change of state has the wrong energy change listed? condensation deposition melting freezing

Physics

2 answers:

ipn [44]3 years ago

6 0

Where are the energy changes?

REY [17]3 years ago

5 0

It's deposition so be. It should say deposition gains when it actually loses energy.

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What type of Circuit do they use in a home? WHY ? (Simple circuit / Parallel circuit / Series circuit) helpp

Vikentia [17]

Answer:

Parallel

Explanation:

Most standard 120-volt household circuits in your home are (or should be) parallel circuits. Outlets, switches, and light fixtures are wired in such a way that the hot and neutral wires maintain a continuous circuit pathway independent from the individual devices that draw their power from the circuit.

Hope that helps :)

7 0

3 years ago

Place these bodies of our solar system in the proper order of formation.

earnstyle [38]

The four inner planets, those closest to the Sun, are Mercury, Venus, Earth, and Mars. They are smaller and composed mainly of metals and rocks. The four outer planets — Jupiter, Saturn, Uranus, and Neptune — are larger and composed mostly of gases.

4 0

3 years ago

Read 2 more answers

How many neutrons are contained in 2 kg? Mass of one neutron is 1.67x10-27 kg.

liraira [26]

Answer:

1.2 × 10^27 neutrons

Explanation:

If one neutron = 1.67 × 10^-27 kg

then in 2kg...the number of neutrons

; 2 ÷ 1.67 × 10^-27

There are.... 1.2 × 10^27 neutrons

4 0

2 years ago

The electric field 2.5 mm from a uniform sheet of charge is σ=800, NC. How much charge is contained in a 5.0x5.0 cm section of t

slamgirl [31]

Answer:

The charge is $2.75\times10^{-13}\ C$

Explanation:

Given that,

Distance = 2.5 mm

Electric field = 800 NC

Length $L=5.0\times5.0\times10^{-4}\ m$

We need to calculate the linear charge density

Using formula of linear charge density

$E=\dfrac{2k\lambda}{r}$

$\lambda=\dfrac{Er}{2k}$

Put the value into the formula

$\lambda=\dfrac{800\times2.5\times10^{-3}}{2\times9\times10^{9}}$

$\lambda=1.1\times10^{-10}\ C/m$

We need to calculate the charge

Using formula of charge

$Q=\lambda\timesL$

Put the value into the formula

$Q=1.1\times10^{-10}\times(5.0\times5.0\times10^{-4})$

$Q=2.75\times10^{-13}\ C$

Hence, The charge is $2.75\times10^{-13}\ C$

5 0

2 years ago

a runner starts from rest and has an acceleration of 3 m/s^2. How fast is she running after 1.1 seconds

grigory [225]

Acceleration x time = velocity

Since you're given acceleration and time, just plug the values into the equation.

3 $\frac{m}{s^{2}}$ x 1.1 s = ?

Solve that equation, and remember your velocity should be in m/s.

8 0

2 years ago