Answer:
Part A
it would take 6 sec
it would take 3 sec
Explanation:
We are told that the power supplied to the wheel is constant which means that the sport car is gaining energy i.e
Hence if power is constantly supplied energy constantly increase
From the formula of the Kinetic energy
we can see that as the speed doubles from 29 mph to 58 mph the energy needed is 
= 4 times of the energy from the formula
Also the time needed would also be 4 times because energy i directly proportional to time
Hence to reach 58mph the time that it would take is
= 
We are told that the ground pushes the car with a constant force and
F = ma
this means that the acceleration is also constant
now from newtons law
v = u +at
Looking at it we see that final velocity is directly proportional with time
hence it would take twice the time to reach twice the final velocity
Time to reach 58mph = 3 s
since time to reach 29 mph(![\frac{1}{2} \ of \ [58mph]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5C%20of%20%5C%20%5B58mph%5D)
) =( 
)1.5 s
The potential energy of a 2-μc charge at that point in space is 
joules.
Given,
V=400v, q=2-μc=2*
,
U(potential energy)=V*q=400*2*= joules.
<h3>Potential energy</h3>
The energy that an item retains due to its position in relation to other objects, internal tensions, electric charge, or other reasons is known as potential energy in physics. The gravitational potential energy of an object is based on its mass and the distance from the centre of mass of another object. Other common types of potential energy include the elastic potential energy of an extended spring and the electric potential energy of an electric charge in an electric field. The joule, denoted by the sign J, is the SI's definition of an energy unit.
The vectors that are described as gradients of a particular scalar function known as potential can be used to represent these forces, also known as conservative forces, at any location in space.
At a certain point in space there is a potential of 400 v. what is the potential energy of a 2-μc charge at that point in space? group of answer choices'
Learn more about potential energy here:
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<span>Z is present outside the solar system.</span>
We can assume the process to be adiabatic such that we can make use of the formula:
W = R (T2 - T1) / (γ - 1)
W = 8.314 (297 - 17) / (1.4 - 1)
W = 700 J/mole
multiplying the number of moles
W = 700 (0.43)
W = 301 J
The work done is 301 J.
