Answer and Explanation:
The rate (in W) at which heat energy moves from the more blazing article to the colder item increments with the temperature distinction between the items.
The more noteworthy the temperature contrast, the more prominent the rate at which exchange of heat energy takes place.
Thus the temperature difference between the beakers relates in the same manner as described above.
The exchange of heat energy continues until a thermal equilibrium is attained.
Answer:
Power output = 
Explanation:
Given:
Mass of the elevator is, 
Height to which it is raised is, 
Acceleration due to gravity is, 
Time taken by the motor to raise the elevator is, 
Now, work done on the elevator by the motor is equal to the increase in the gravitational potential energy of the elevator.
Increase in gravitational potential energy is given as:

Therefore, work done by motor is, 
Now, we know that, power is work done in unit time. So, power output is given as:
![Power=\frac{W}{t}\\\\Power=\frac{10\times 10^4\ J}{5.0\ s}\\\\Power=2\times 10^4\ J/s\\\\Power=2\times 10^4\ W..........[1 W = 1\ J/s]](https://tex.z-dn.net/?f=Power%3D%5Cfrac%7BW%7D%7Bt%7D%5C%5C%5C%5CPower%3D%5Cfrac%7B10%5Ctimes%2010%5E4%5C%20J%7D%7B5.0%5C%20s%7D%5C%5C%5C%5CPower%3D2%5Ctimes%2010%5E4%5C%20J%2Fs%5C%5C%5C%5CPower%3D2%5Ctimes%2010%5E4%5C%20W..........%5B1%20W%20%3D%201%5C%20J%2Fs%5D)
Therefore, the power output of the first motor is 
Answer:
The mass is 16 [g]
Explanation:
We have to remember the formula that defines density, which mentions that the density is equal to mass divided by the volume.
![Density = mass / volume\\where:\\density = 2[\frac{g}{cm^{3} } ]\\Volume = 8 [cm^{3}]](https://tex.z-dn.net/?f=Density%20%3D%20mass%20%2F%20volume%5C%5Cwhere%3A%5C%5Cdensity%20%3D%202%5B%5Cfrac%7Bg%7D%7Bcm%5E%7B3%7D%20%7D%20%5D%5C%5CVolume%20%3D%208%20%5Bcm%5E%7B3%7D%5D)
Now we clear the mass:
![mass= density*volume\\mass = 2[\frac{g}{cm^{3} }]*8[cm^{3} ]\\mass = 16 [g]](https://tex.z-dn.net/?f=mass%3D%20density%2Avolume%5C%5Cmass%20%3D%202%5B%5Cfrac%7Bg%7D%7Bcm%5E%7B3%7D%20%7D%5D%2A8%5Bcm%5E%7B3%7D%20%5D%5C%5Cmass%20%3D%2016%20%5Bg%5D)
Answer:
See attached document
Explanation:
Entire process for deriving the asked expression dV across the bridge as function of dP is illustrated in the attachment below.
The document gives a step-by step process for arriving at the expression. However, manipulation of algebraic equations is skipped for the conciseness of the document.
It also gives the expression for the case when all resistors have different nominal values.
Answer:
I was going to give you the paper where I saw it but since you are not giving enough points I can not give you so I am only going to give you some of these that are here sorry
Explanation:
1.

x=5

7.
5,12,13
9.
