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3 years ago

8

Please help! Answer and explain

1 answer:

evablogger [386]3 years ago

3 0

Answer:

A

Explanation:

The asteroid belt is the farthest from the sun, so that means it will take the longest to orbit.

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) In the Tour de France, a bicyclist races up two successive (straight) hills of

son4ous [18]

it Bob btw

so the total km would be 399km

hope it helps

3 0

3 years ago

If the observed test value of a hypothesis test is outside of the established critical value(s), a researcher would __________.

sashaice [31]

I just had this question, the awnser is A.

6 0

3 years ago

Read 2 more answers

The sun is more massive than the moon, but the sun is farther from the earth. Which one exerts a greater gravitational force on

love history [14]

Answer:

178.4 times

Explanation:

We have Newton formula for attraction force between 2 objects with mass and a distance between them:

$F_G = G\frac{M_1M_2}{R^2}$

where $G =6.67408 × 10^{-11} m^3/kgs^2$ is the gravitational constant on Earth. $M_1, M_2$ is the masses of the 2 objects. and R is the distance between them.

From here we can calculate the ratio of gravitational force between the moon and the sun

$\frac{F_s}{F_m} = \frac{G\frac{MM_s}{R_s^2}}{G\frac{MM_m}{R_m^2}}$

We can divide the top and bottom by G and M

$\frac{F_s}{F_m}= \frac{M_s}{R_s^2}:\frac{M_m}{R_m^2}$

$= \frac{M_s}{R_s^2}\frac{R_m^2}{M_m}$

$= \frac{M_s}{M_m}(\frac{R_m}{R_s})^2$

$= \frac{1.99*10^{30}}{7.35*10^{22}}(\frac{3.85*10^8}{1.5*10^{11}})^2$

$= 27074830*6.59*10^{-6} = 178.4$

So the gravitational force of the sun is about 178 times greater than that of the moon to an object on Earth

5 0

3 years ago

A object is 200 miles from the center of a circle and makes a circuit every 2 hours. How fast is it moving?

Tanya [424]

Answer: 628.31 miles/h

Explanation:

The equation to calculate the average speed $s$ of an object moving in a circular path is:

$s=\frac{2 \pi r}{T}$ (1)

Where:

$r=200 miles$ is the radius of the circumference

$T=\frac{1}{f}$ is the period, which has an inverse relation with the frequency $f=\frac{1 circuit}{2 h}=0.5 h^{-1}$ . Then $T=\frac{1}{0.5 h^{-1}}=2 h$

Solving the equation:

$s=\frac{2 \pi (200 miles)}{2 h}$ (2)

$s=628.31 miles/h$ (3)

4 0

3 years ago

What is the transmitted intensity of light if unpolarized light passes through a single polarizing filter and the initial intens

Gennadij [26K]

Answer:

The transmitted intensity is $I = 40 \ W/m^2$

Explanation:

From the question we are told that

The intensity of the unpolarized light $I_o = 80 \ W /m^2$

Generally for a single filter the transmitted intensity of light is mathematically evaluated as

$I = \frac{I_o}{2}$

substituting values

$I = \frac{80}{2}$

$I = 40 \ W/m^2$

4 0

3 years ago