Artificial gravity is created by rotating the cylinder
So here we can say that the acceleration is due to centripetal acceleration
So here we know that the formula of centripetal acceleration is given by

so here we know that


now we will plug in all values



So above is the radius of the cylinder
Now to find the diameter



so its diameter is 194.8 m
I’m just answering questions
Answer:
a) 6.9*10^14 Hz
b) 9*10^-12 T
Explanation:
Given that
The wavelength of the wave, λ = 435 nm
Amplitude of the electric field, E(max) = 2.7*10^-3 V/m
a)
The frequency of the wave can be found by using the formula
c = fλ, where c = speed of light
f = c/λ
f = 3*10^8 / 435*10^-9
f = 6.90*10^14 Hz
b)
E(max) = B(max) * c, magnetic field amplitude, B(max) =
B(max) = E(max)/c
B(max) = 2.7*10^-3 / 3*10^8
B(max) = 9*10^-12 T
c)
1T = 1 (V.s/m^2)
Answer:
The acceleration of the object is 9.3 m/s²
Explanation:
For a straight movement with constant acceleration, this equation for the position applies:
x = x0 + v0 t + 1/2 a t²
where
x = position at time t
x0 = initial position
v0 = initial velocity
a = acceleration
t = time
we have two positions: one at time t = 1 s and one at time t = 2 s. We know that the difference between these positions is 14.0 m. These are the equations we can use to obtain the acceleration:
x₁ = x0 + v0 t + 1/2 a (1 s)²
x₂ = x0 + v0 t + 1/2 a (2 s)²
x₂ - x₁ = 14 m
we know that the object starts from rest, so v0 = 0
substracting both equations of position we will get:
x₂ - x₁ = 14
x0 + v0 t + 1/2 a (2 s)² - (x0 + v0 t + 1/2 a (1 s)²) = 14 m
x0 + v0 t + 2 a s² - x0 -v0 t - 1/2 a s² = 14 m
2 a s² - 1/2 a s² = 14 m
3/2 a s² = 14 m
a = 14 m / (3/2 s²) = <u>9.3 m/s² </u>
Given that,
The electric field is given by,

Suppose, B is the amplitude of magnetic field vector.
We need to find the complete expression for the magnetic field vector of the wave
Using formula of magnetic field
Direction of
vector is the direction of propagation of the wave .
Direction of magnetic field = 

We need to calculate the poynting vector
Using formula of poynting

Put the value into the formula


Hence, The poynting vector is 