Answer:
The width of the slit is 0.167 mm
Explanation:
Wavelength of light, 
Distance from screen to slit, D = 88.5 cm = 0.885 m
The distance on the screen between the fifth order minimum and the central maximum is 1.61 cm, y = 1.61 cm = 0.0161 m
We need to find the width of the slit. The formula for the distance on the screen between the fifth order minimum and the central maximum is :
where
a = width of the slit
a = 0.000167 m
a = 0.167 mm
So, the width of the slit is 0.167 mm. Hence, this is the required solution.
Answer:
Density is independent of the
amount of the sample. (D)
Explanation:
Because density is an intrinsic property of matter.
hope it helps!
Hey there!
Here is your answer:
<u><em>The proper answer to this question is option C "</em></u><span><u><em>0.00349".</em></u>
Reason:
</span><span><u><em>1 L = 100 cL. Or 1 cL = 0.01 L</em></u>
</span><span><u><em>34.9 cL = 34.9 / 100 L = 0.349 L</em></u>
</span><span><u><em> 1 hL = 100 L. 0.349 L = 0.349 / 100 hL = 0.00349 hL</em></u>
<em>Therefore the answer is option C!</em>
If you need anymore help feel free to ask me!
Hope this helps!
~Nonportrit</span>
The #1 answer would be meats and eggs. But, as a veggan, I present you with meatless protien-rich food!
1 - <u>Pea protein</u> (used in Beyond Meat, which tastes just like meat btw!)
2 - <u>Soy protein</u> such as tofu
3 - <u>Nuts</u>
4 - <u>Beans</u>! oml so many beans have MORE protien than meat!! ikr!?!?
may I have Brainliest pls =)
Answer:
m = 3 kg
The mass m is 3 kg
Explanation:
From the equations of motion;
s = 0.5(u+v)t
Making t thr subject of formula;
t = 2s/(u+v)
t = time taken
s = distance travelled during deceleration = 62.5 m
u = initial speed = 25 m/s
v = final velocity = 0
Substituting the given values;
t = (2×62.5)/(25+0)
t = 5
Since, t = 5 the acceleration during this period is;
acceleration a = ∆v/t = (v-u)/t
a = (25)/5
a = 5 m/s^2
Force F = mass × acceleration
F = ma
Making m the subject of formula;
m = F/a
net force F = 15.0N
Substituting the values
m = 15/5
m = 3 kg
The mass m is 3 kg
