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Alex787 [66]
2 years ago
8

A car is traveling at 30m/s it accelerates steadily for 5 s after which it is travelling at 50 m/s calculate its acceleration?

Physics
2 answers:
Natalka [10]2 years ago
7 0
Formula for acceleration: a = v-v0/t
a is acceleration, v is final velocity and v0 is starting velocity, t is time
Now plug it in
a = 50m/s - 30 m/s = 20 m/s/ 5s = 4 m/s^2
The acceleration is 4 m/s^3
Mashcka [7]2 years ago
4 0
For this question , we should apply
a = v - u by t
Given - u = 30m/s
v = 50m/s
t = 5 secs
Solution :
a = v - u by t
a = 50 - 30 by 5
a = 20 by 5
( cut 5 and 20 because 5 x 4 = 20 )
a = 4 m/s^2

.:. The acceleration is 4 m/s^2
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What is the mechanical advantage of a nail puller where you exert a force 45 cm from the pivot and the nail is 1.8 cm on the oth
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Answer:

Explanation:

Mechanical Advantage is the ratio of the distance of the input load (Li)from the pivot to the output load applied to the pivot(Lo)

MA = Li/Le

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MA = 45/1.8

MA = 25

Hence the mechanical advantage is 25

Also MA is expressed in terms of the force ratio which is the ratio of the Load to the effort applied.

MA = Load/Effort

Given

Load = 1250N

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Effort = ?

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25 = 1250/Effort

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2 years ago
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6 0
3 years ago
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A slender rod is 80.0 cm long and has mass 0.390 kg . A small 0.0200-kg sphere is welded to one end of the rod, and a small 0.05
Keith_Richards [23]

Answer

given,

length of slender rod =80 cm = 0.8 m

mass of rod = 0.39 Kg

mass of small sphere = 0.0200 kg

mass of another sphere weld = 0.0500 Kg

calculating the moment of inertia of the system

I = \dfrac{ML^2}{12}+\dfrac{m_1L^2}{4}+\dfrac{mL^2}{4}

I = \dfrac{0.39\times 0.8^2}{12}+\dfrac{0.02\times 0.8^2}{4}+\dfrac{0.05\times 0.8^2}{4}

I =0.032\ kg.m^2

using conservation of energy

\dfrac{1}{2}I\omega^2 = (m_1-m_2)g\dfrac{L}{2}

\omega=\sqrt{\dfrac{(m_1-m_2)gL}{I}}

\omega=\sqrt{\dfrac{(0.05-0.02)\times 9.8 \times 0.8}{0.032}}

\omega=2.71 \rad/s

we know,

v = r ω

v = \dfrac{L}{2} \times 2.71

v = \dfrac{0.8}{2} \times 2.71

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3 years ago
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kirill [66]

Explanation:

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7 0
2 years ago
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Two loudspeakers emit sound waves along the x-axis. The sound has maximum intensity when the speakers are 19 cm apart. The sound
Roman55 [17]

Answer:

a.96cm

b.77cm

Explanation:

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Lowest intensity,d_2=29cm

d_1+d_2=19+29=48cm  

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b. From a, above we know that half-wavelength is 48cm

Also, the distance of known  maximum is 29cm

Next maximum is calculated as:

Next \m\aximum=Last \ Maximum+ \ 0.5Wavelength\\=29cm+48cm\\=77cm

The next maximum will occur at 77cm

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