The potential energy of the car at the top of the ramp is greater than the kinetic energy of the car at the bottom of the ramp
Explanation:
Here we have a car moving down along a ramp. In absence of force of friction, the total mechanical energy of the car while moving down would be conserved:
![E=PE+KE = const.](https://tex.z-dn.net/?f=E%3DPE%2BKE%20%3D%20const.)
where
PE is the potential energy
KE is the kinetic energy
However, this is not true if friction acts on the car. When the car is still at the top of the ramp, its speed is zero, so its kinetic energy is zero, and all the energy is just potential energy:
![E=PE](https://tex.z-dn.net/?f=E%3DPE)
While the car moves down along the ramp, friction does work on it, and part of the total mechanical energy is wasted and converted into thermal energy. As a result, the car reaches the bottom of the ramp with a final energy which is less than the initial energy:
![E'](https://tex.z-dn.net/?f=E%27%3CE)
Also, at the bottom of the ramp, all the energy is just kinetic energy, since the height of the car is now zero, so
![E'=KE](https://tex.z-dn.net/?f=E%27%3DKE)
It follows that
![KE](https://tex.z-dn.net/?f=KE%3CPE)
So, the potential energy of the car at the top of the ramp is greater than the kinetic energy of the car at the bottom of the ramp.
Learn more about potential and kinetic energy:
brainly.com/question/6536722
brainly.com/question/1198647
brainly.com/question/10770261
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