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2 years ago

A paper clip moves towards a magnet lying on a table. What forces are present in this situation? How do these forces compare?

Physics

1 answer:

Hatshy [7]2 years ago

5 0

The magnet is at a gravitational force while the paper clip is at an applied force

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A major process by which the Sun's energy is transported around the Earth system?

Setler79 [48]

Is it Conduction. Here's my theory e<span>nergy is transferred between the earth's surface and the atmosphere by Conduction, Convection and Radiation.</span>

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3 years ago

3. The pressure at the bottom of the ocean is great enough to crush submarines with steel walls that are 10 centimeters thick. S

Elden [556K]

Answer:

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2 years ago

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Water is flowing in a pipe with a circular cross section but with varying cross-sectional area, and at all points the water comp

slamgirl [31]

(a) 5.66 m/s

The flow rate of the water in the pipe is given by

$Q=Av$

where

Q is the flow rate

A is the cross-sectional area of the pipe

v is the speed of the water

Here we have

$Q=1.20 m^3/s$

the radius of the pipe is

r = 0.260 m

So the cross-sectional area is

$A=\pi r^2 = \pi (0.260 m)^2=0.212 m^2$

So we can re-arrange the equation to find the speed of the water:

$v=\frac{Q}{A}=\frac{1.20 m^3/s}{0.212 m^2}=5.66 m/s$

(b) 0.326 m

The flow rate along the pipe is conserved, so we can write:

$Q_1 = Q_2\\A_1 v_1 = A_2 v_2$

where we have

$A_1 = 0.212 m^2\\v_1 = 5.66 m/s\\v_2 = 3.60 m/s$

and where $A_2$ is the cross-sectional area of the pipe at the second point.

Solving for A2,

$A_2 = \frac{A_1 v_1}{v_2}=\frac{(0.212 m^2)(5.66 m/s)}{3.60 m/s}=0.333 m^2$

And finally we can find the radius of the pipe at that point:

$A_2 = \pi r_2^2\\r_2 = \sqrt{\frac{A_2}{\pi}}=\sqrt{\frac{0.333 m^2}{\pi}}=0.326 m$

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2 years ago

Heredity appears to have a large effect on the intelligence of adults than environment. True False

Annette [7]

I JUST WANT THE ANSWER

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2 years ago

A piece of aluminum foil has a known surface density of

bija089 [108]

The cube has 6 equal, square, foil faces. The mass of foil for each face is (380/6) milligrams.

The surface area of each piece is (380)/(6•11) cm^2.

The length of each side of the piece is √(380/6•11) cm

That's about 2.4 cm .

It's a cute little foil cube, just under 1-inch each way.

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3 years ago