Answer:
You need to use charts or a calculator to get 56%
Explanation:
Answer:
C
Explanation:
the plant cools itself down by allowing water to evaporate from their leaves so it doesn't need water to cool down
<em>Resultant angle; θ = 25.59° </em>
This question is dealing with bearings and distance.
We are told that from point A, the camel walks 20 km at 15° in the south of east direction.
Thus, d_s,e = 20 km
Resolving along the horizontal east direction gives; d_e = 20 cos 15
d_e = 19.32 km
Also, resolving along the vertical south direction gives; d_s = 20 sin 15
d_s = 5.18 km
Net vertical distance; d_vert = 8km - 5.18km = 2.72 km
Net horizontal distance; d_hor = 25km - 19.32 km = 5.68 km
Now, the resultant angle is given by;
tan θ = d_vert/d_hor
tan θ = 2.72/5.68
tan θ = 0.4789
θ = tan^(-1) 0.4789
θ = 25.59°
Read more at; brainly.com/question/22518031
Answer:
During a chemical reaction, Bromine (Br) would be expected to <u><em>gain 1 valence electron to have a full octet.</em></u>
Explanation:
In the periodic table the elements are ordered so that those with similar chemical properties are located close to each other.
The elements are arranged in horizontal rows, called periods, which coincide with the last electronic layer of the element. That is, an element with five electronic shells will be in the fifth period.
The columns of the table are called groups. The elements that make up each group coincide in their electronic configuration of valence electrons, that is, they have the same number of electrons in their last.
The elements tend to resemble the closest noble gases in terms of their electronic configuration of the last layer, that is, having eight electrons in the last layer to be stable.
Bromine belongs to group 17 (VII A), which indicates that it has 7 electrons in its last shell. So bromine requires more energy to lose all 7 electrons and generate stability, than it does to gain 1 electron and fill in 8 electrons to be stable. So:
<u><em>During a chemical reaction, Bromine (Br) would be expected to gain 1 valence electron to have a full octet.</em></u>
The orbital period of the satellite[T] is given as 
.
The radius of the satellite is given [R] 
.
we are asked here to calculate the tangential speed of the satellite.
Before going to get the solution first we have understand the tangential speed.
The tangential speed of a satellite is given as the speed required to keep the satellite along the orbit. If satellite speed is less than tangential speed,there is the chance of it falling down towards earth. If it is more,then it will deviate from it orbit and can't stick to the orbit further.In a simple way the tangential speed is the linear speed of an object in a circular path.
Now we have to calculate the tangential speed [V].
Mathematically the tangential speed [V] written as -
V
where T is the time period of the satellite and R is the radius of the satellite.
There is also another way through which we can get the solution as explained below-
We know that the tangential speed of a satellite V
where G is the gravitational constant and M is the mas of central object.
But we know that 
⇒
where g is the acceleration due to gravity of that central object.
Hence 
⇒ 
By knowing the value of g due to that central object we can also calculate its tangential speed.
