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pochemuha
3 years ago
7

If acids are compounds that release protons (h+), how is it that sox and nox cause acid rain?

Chemistry
1 answer:
tino4ka555 [31]3 years ago
3 0
The protons come from water. Sulfur oxides dissolve in water to form sulfurous and sulfuric acids, and nitrogen oxides dissolve to form nitrous and nitric acids.
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20)
anyanavicka [17]

Answer:

D

Explanation:

7 0
3 years ago
What do colligative properties depend on?
oee [108]
Colligative properties depend on the amount of solute dissolved in a solvent. These set of properties do not depend on the type of species present. These properties include freezing point depression, boiling point elevation, osmotic pressure and vapor pressure lowering.
5 0
3 years ago
Read 2 more answers
Could someone explain how they got this answer, explain step by step plz
gulaghasi [49]

Answer:

6.018 amu

Explanation:

Let 6–Li be isotope A.

Let 7–Li be isotope B.

Let the abundance of 6–Li be A%

Let the abundance of 7–Li be B%

The following data were obtained from the question:

Atomic mass of isotope A (6–Li) =.?

Atomic mass of isotope B (7–Li ) = 7.015 amu.

Abundance of 7–Li (B%) = 92.58%

Abundance of 6–Li (A%) = 100 – B% = 100 – 92.58 = 7.42%

Atomic mass of Lithium = 6.941amu

The atomic mass of isotope A (6–Li) can be obtained as follow:

Atomic mass = [(Mass of A x A%)/100] + [(Mass of B x B%)/100]

6.941 = [(mass of A x 7.42)/100] + [(7.015x92.58)/100]

6.941 = [(mass of A x 7.42)/100] + 6.494487

(mass of A x 7.42)/100 = 6.941 – 6.494487

(mass of A x 7.42)/100 = 0.446513

Mass of A x 7.42 = 100 x 0.446513

Mass of A x 7.42 = 44.6513

Divide both side by 7.42

Mass of A = 44.6513 / 7.42

Mass of A = 6.018 amu

Therefore, the mass of 6–Li is 6.018 amu

7 0
3 years ago
Is O2 always a double bond?
Dima020 [189]
  • O-O single bonds and H-O single bonds in \text{H}_2\text{O}_2 molecules.
  • H-O single bonds in \text{H}_2\text{O} molecules.
  • O=O double bonds in \text{O}_2 molecules.
<h3>Explanation</h3>

How many valence electrons do atoms in each molecule need for them to be stable?

  • Each H atom needs two valence electrons to be stable.
  • Each atom of an element other than H needs eight valence electron to be stable.
  • There are two H atoms and two O atoms in an  \text{H}_2\text{O}_2 molecule. Atoms in each \text{H}_2\text{O}_2 need 2 \times 1 + 2\times 2 = 6 more electrons to be stable.
  • There are two H atoms and one O atom in an \text{H}_2\text{O} molecule. Atoms in each \text{H}_2\text{O} molecule need 2 \times 1 + 2= 4 more electrons to be stable.
  • There are two O atoms in an \text{O}_2 molecule. Atoms in each \text{O}_2 molecule need 2 \times 2 = 4 more electrons to be stable.

How many chemical bonds in each molecule?

Each chemical bond adds one valence electron to each bonding atom. Each chemical bond connects two atoms. As a result, each chemical bond adds two valence electrons to the molecule.

  • Each \text{H}_2\text{O}_2 molecule needs 6 / 2 = 3 chemical bonds.
  • Each \text{H}_2\text{O} molecule needs 4 / 2 = 2 chemical bonds.
  • Each \text{O}_2 molecule needs 4 /2= 2 chemical bonds.

What chemical bonds are these? Again, each H atom needs only one more valence electron to be stable. It will share only one electron with O and form one H-O bond. The rest of the chemical bonds are between O atoms.

  • There are two H atoms in each \text{H}_2\text{O}_2 molecule, which form two H-O bonds. Two of the three chemical bonds in this molecule are H-O. The other is an O-O single bond between the two O atoms.
  • There are two H atoms in each \text{H}_2\text{O} molecule, which form two H-O bonds. Both chemical bonds in this molecule are H-O. There's no O-O bond in this molecule.
  • There is no H atom in \text{O}_2 molecules. Both chemical bonds are between O atoms. However, there are only two O atoms. There must be two chemical bonds between the two O atoms. That bond will be an O-O double bond.
3 0
3 years ago
Read 2 more answers
Calcium chromate, cacro4, has a ksp of 7.1×10−4. what happens when calcium and chromate solutions are mixed to give 0.0200 m ca2
Serjik [45]

The solubility equilibrium of CaCrO_{4}:

[tex] CaCrO_{4}(aq)<===>Ca^{2+}(aq) + CrO_{4}^{2-}(aq)\\
Q_{sp}=[Ca^{2+}][CrO_{4}^{2-}]\\
= (0.0200 M)(0.0300 M) \\
= 0.0006

Ksp (0.00071) > Qsp (0.0006). So, <u>no precipitate would form</u>.

8 0
3 years ago
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