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3 years ago

Are the fragments all the same size or shape

1 answer:

7 0

Hey there! I believe this statement is False. No two fragments are exactly the same size, and all fragments vary on the density of the material, the speed at which it broke off of the material, and the amount of it that hit the ground. Because of this, some people may say "Oh, this is the same size as this," but in reality, nothing is exactly the same size. At least, on a molecular level. So the statement above is false.

Hope this helped!

Thanks!

~Steve

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In addition to the two types of motion found in liquids, gases have What kind of motion

makvit [3.9K]

Answer:

In liquids, particles are quite close together and move with random motion throughout the container. Particles move rapidly in all directions but collide with each other more frequently than in gases due to shorter distances between particles.

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3 years ago

When magnesium reacts with hydrochloric acid, hydrogen gas is produced. The amount of gas produced is dependent upon the concent

velikii [3]

Answer:

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2 years ago

Does it take more, less, or the same amount of heat to melt 1.0 kg of ice at 0°C, or to bring 1.0 kg of liquid water at 0°C to t

Murljashka [212]

Answer : It takes less amount of heat to metal 1.0 Kg of ice.

Solution :

The process involved in this problem are :

$(1):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(2):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)$

Now we have to calculate the amount of heat released or absorbed in both processes.

For process 1 :

$Q_1=m\times \Delta H_{fusion}$

where,

$Q_1$ = amount of heat absorbed = ?

m = mass of water or ice = 1.0 Kg

$\Delta H_{fusion}$ = enthalpy change for fusion = $3.35\times 10^5J/Kg$

Now put all the given values in $Q_1$ , we get:

$Q_1=1.0Kg\times 3.35\times 10^5J/Kg=3.35\times 10^5J$

For process 2 :

$Q_2=m\times c_{p,l}\times (T_{final}-T_{initial})$

where,

$Q_2$ = amount of heat absorbed = ?

m = mass of water = 1.0 Kg

$c_{p,l}$ = specific heat of liquid water = $4186J/Kg^oC$

$T_1$ = initial temperature = $0^oC$

$T_2$ = final temperature = $100^oC$

Now put all the given values in $Q_2$ , we get:

$Q_2=1.0Kg\times 4186J/Kg^oC\times (100-0)^oC$

$Q_2=4.186\times 10^5J$

From this we conclude that, $Q_1$ that means it takes less amount of heat to metal 1.0 Kg of ice.

Hence, the it takes less amount of heat to metal 1.0 Kg of ice.

5 0

3 years ago

Can someone pls help me with this question

artcher [175]

Answer:

The answer to your question is 24.325

Explanation:

Data

Magnesium-24 Abundance = 78.70%

Magnesium-25 Abundance = 10.13%

Magnesium-26 Abundance = 11.17%

Process

1.- Convert the abundance to decimals

Magnesium-24 Abundance = 78.70/100 = 0.787

Magnesium-25 Abundance = 10.13/100 = 0.1013

Magnesium-26 Abundance = 11.17/100 = 0.1117

2.- Write an equation

Average atomic mass = (Atomic mass-1 x Abundance 1) + (Atomic mass 2 x

Abundance-2) + (Atomic mass 3 x Abundance 3)

3.- Substitution

Average atomic mass = (24 x 0.787) + (25 x 0.1013) + (26 x 0.1117)

4.- Simplification

Average atomic mass = 18.888 + 2.533 + 2.904

5.- Result

Average atomic mass = 24.325

5 0

3 years ago

Hi. I need help with this

Vlad1618 [11]

Factors that determine ionization energy:

Electronic Repulsion - If the electronic density decreases, the ionization energy with increase and vice versa. If an electron gets released, it decreases the electronic repulsion. This makes releasing another electron harder than the first on unless the electron that is being released comes from another energetic level.
# Of Energy Levels - The more energy cores that get filled up, the more ionization levels decrease. When we see the energy levels go from top to bottom, the ionization also go from most to least. This is why ionization occurs on the highest level.
Nuclear Charge - The higher the atomic number, the higher charge in the nuclei. This also makes the ionization energy higher as it increases from left to right of in other words, if the nuclear charge gets higer, the energy gets higher as well.

Factors that determine atomic volume:

How many protons are in the nucleus (nuclear charge)
How many energy levels carry electrons (electrons in outer energy level)

Best of Luck!

4 0

3 years ago