V(rms) = √(3RT/M)
Where R is the molar gas constant with value 8.314 and T is the temperature in Kelvin and M is the molar mass
v(rms F₂) = √(3 x 8.314 x 304 / 38)
v(rms F₂) = 14.1 m/s
v(rms Cl₂) = √(3 x 8.314 x 304 / 71)
v(rms Cl₂) = 10.3 m/s
v(rms Br₂) = √(3 x 8.314 x 304 / 160)
v(rms Br₂) = 6.88 m/s
Answer:
The given sample is aluminum.
Explanation:
Given data:
Mass of unknown sample = 54 g
Volume of given sample = 20cm³
Is sample is Al = ?
Solution:
In order to solve this problem we must know the density of Al from literature.
density of Al = 2.7 g/cm³
Now we will calculate the density of given unknown sample.
d = m/v
d = 54 g/ 20cm³
d = 2.7 g/cm³
Thus given sample is aluminum.
Answer: This may result in the protein forming bonds with additional amino acids, this may result in the protein forming bonds with lipids instead of other proteins
Explanation:..
Answer:
C- a method of testing an idea