Answer:
Visible light
X rays
ultraviolet radiation
gamma rays
microwave radiation
Explanation:
Electromagnetic waves consist of oscillating electric and magnetic fields which vibrate in a direction perpendicular to the direction of motion of the wave (transverse wave). Electromagnetic waves have all same speed in a vacuum (, known as speed of light) and are classified into 7 different types according to their frequency and wavelength. This classification is called electromagnetic spectrum.
From lowest to highest wavelength, the 7 types are:
Gamma rays
X-rays
Ultraviolet radiation
Visible light
Infrared radiation
Microwaves
Radio waves
Sound waves, on the contrary, do not belong to the electromagnetic spectrum, since they are another type of wave called mechanical waves (which consist of vibrations of the particles in a medium).
The De Broglie's wavelength of a particle is given by:
where
is the Planck constant
p is the momentum of the particle
In this problem, the momentum of the electron is equal to the product between its mass and its speed:
and if we substitute this into the previous equation, we find the De Broglie wavelength of the electron:
So, the answer is True.
Answer:
When we double the angular velocity the maximum acceleration will changes by a factor of 4.
Explanation:
Given the angular frequency of the simple harmonic oscillator is doubled.
We need to find the change in the maximum acceleration of the oscillator.
Now, according to the problem, the angular frequency got doubled.
Let us plug . Then the maximum acceleration will be
We can see, when we double the angular velocity the maximum acceleration will changes by a factor of 4.
Answer:
0.54454
104.00902 N
Explanation:
m = Mass of wheel = 100 kg
r = Radius = 0.52 m
t = Time taken = 6 seconds
= Final angular velocity
= Initial angular velocity
= Angular acceleration
Mass of inertia is given by
Angular acceleration is given by
Equation of rotational motion
The coefficient of friction is 0.54454
At r = 0.25 m
The force needed to stop the wheel is 104.00902 N