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DiKsa [7]
3 years ago
14

Which of the following are found within the electromagnetic spectrum? Check all that apply. sound waves visible light X rays ult

raviolet radiation gamma rays microwave radiation
Physics
1 answer:
sattari [20]3 years ago
8 0

Answer:

Visible light

X rays

ultraviolet radiation

gamma rays

microwave radiation

Explanation:

Electromagnetic waves consist of oscillating electric and magnetic fields which vibrate in a direction perpendicular to the direction of motion of the wave (transverse wave). Electromagnetic waves have all same speed in a vacuum (c=3.0\cdot 10^8 m/s, known as speed of light) and are classified into 7 different types according to their frequency and wavelength. This classification is called electromagnetic spectrum.

From lowest to highest wavelength, the 7 types are:

Gamma rays

X-rays

Ultraviolet radiation

Visible light

Infrared radiation

Microwaves

Radio waves

Sound waves, on the contrary, do not belong to the electromagnetic spectrum, since they are another type of wave called mechanical waves (which consist of vibrations of the particles in a medium).

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The electric field 2.5 mm from a uniform sheet of charge is σ=800, NC. How much charge is contained in a 5.0x5.0 cm section of t
slamgirl [31]

Answer:

The charge is 2.75\times10^{-13}\ C

Explanation:

Given that,

Distance = 2.5 mm

Electric field = 800 NC

Length L=5.0\times5.0\times10^{-4}\ m

We need to calculate the linear charge density

Using formula of linear charge density

E=\dfrac{2k\lambda}{r}

\lambda=\dfrac{Er}{2k}

Put the value into the formula

\lambda=\dfrac{800\times2.5\times10^{-3}}{2\times9\times10^{9}}

\lambda=1.1\times10^{-10}\ C/m

We need to calculate the charge

Using formula of charge

Q=\lambda\timesL

Put the value into the formula

Q=1.1\times10^{-10}\times(5.0\times5.0\times10^{-4})

Q=2.75\times10^{-13}\ C

Hence, The charge is 2.75\times10^{-13}\ C

5 0
3 years ago
What is the magnitude of the electric field strength between them, if the potential 7.95 cm from the zero volt plate (and 2.05 c
Dmitriy789 [7]

Answer:

ΔVab = Ed

ΔVab = Va-Vb = Va-V0 = Va

E = Va/ d

   = 413V / 0.0795 m

    = 5194.97 V/M

Explanation:

the potential difference between two uniform plates is calculated by the formula of electric field.

6 0
3 years ago
Suppose you were asked to find the torque about point p due to the normal force n in terms of given quantities. which method of
igomit [66]

Answer:

T=Lnsin\alpha

Please check the attached

Explanation:

The torque can simply be calculated by multiplying the length of the rod by the perpendicular force n as shown in the attached figure.

Note that sin90=1

T=Lsin\alpha(nsin90)

T=Lsin\alphaxn

T=Lnsin\alpha

7 0
3 years ago
PLEASE HELP MEEEEEE!!!!!!!!!!!!!!!!!!
Simora [160]
You would need to freeze it in a freezer. Hope this helps if it does could I have brainlist thanks
5 0
3 years ago
Read 2 more answers
If you shout at a cliff wall that is 440 m away and the air temperature is at 25 °C, how long will it take before you hear your
ira [324]
The speed of sound at T=25°C is Vs=346 m/s. So the sound has to reach the cliff and return back to you so the path it needs to travel is s=2*440 m = 880 m.
Since the speed of sound is constant s=Vs*t, and t= s/Vs=880/346=2.54335 s. You will hear the echo after t=2.54335 s after you shouted. 
7 0
3 years ago
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