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Nataly [62]
3 years ago
14

A particle is moving in a straight line.at t second, it acceleration is (4-kt), where k is a constant. when t=6, the acceleratio

n of a particle is zero determine its velocity as a function of time​
Physics
1 answer:
baherus [9]3 years ago
4 0

Answer:

v = 4t - t²/3

Explanation:

4 - k*6 = 0

k = 4/6 = 2/3

dv/dt = 4- 2/3 t

integral of dv = integral of (4-2/3 t) dt

v = 4t - t²/3

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What is the equation describing the motion of a mass on the end of a spring which is stretched 8.8 cm from equilibrium and then
Sedbober [7]

Answer:

x=(0.088m)\cos(\sqrt{\frac{k}{m} }  t)

Explanation:

We first identify the elements of this simple harmonic motion:

The amplitude A is 8.8cm, because it's the maximum distance the mass can go away from the equilibrium point. In meters, it is equivalent to 0.088m.

The angular frequency ω can be calculated with the formula:

\omega =\sqrt{\frac{k}{m}}

Where k is the spring constant and m is the mass of the particle.

Now, since the spring starts stretched at its maximum, the appropriate function to use is the positive cosine in the equation of simple harmonic motion:

x=A\cos(\omega t)

Finally, the equation of the motion of the system is:

x=(0.088m)\cos(\omega t)

or

x=(0.088m)\cos(\sqrt{\frac{k}{m} }  t)

7 0
4 years ago
A bus decreases its speed
eduard

Answer:

-6 km/h per minute

Explanation:

7 0
3 years ago
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Explanation:

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7 0
3 years ago
A centrifuge in a medical laboratory rotates at an
suter [353]

Answer:

- 273.77 rad/s^2

Explanation:

fo = 3800 rev/min = 3800 / 60 rps = 63.33 rps

f = 0

ωo = 2 π fo = 2 x 3.14 x 63.33 = 397.71 rad/s

ω = 2 π f = 0

θ = 46 revolutions = 46 x 2π radian = 288.88 radian

Let α be the angular acceleration of the centrifuge

Use third equation of motion for rotational motion

\omega^{2}=\omega _{0}^{2}+2\alpha \theta

0^{2}=397.71^{2}+2 \times \alpha \times 288.88

α = - 273.77 rad/s^2

4 0
3 years ago
A particle with negative charge q and mass m = 2.65×10−15 kg is traveling through a region containing a uniform magnetic field B
Norma-Jean [14]

Answer:

q = 2,95 10-6 C

Explanation:

The magnetic force on a particle is described by the equation

      F = q v x B

Where bold indicate vectors

Let's make the vector product

      vxB =\left[\begin{array}{ccc}i&j&k\\-3&4&12\\0&0&-0.13\end{array}\right]

                     

      v x B = 1.20 106 [i ^ (4 0.130) - j ^ (3 0.130)]

      vx B = 1.20 106 [0.52 i ^ - 0.39j ^]

As they give us the force module, let's use Pythagoras' theorem,

     |v xB | =1.20 10⁶ √( 0.52² + 0.39²)

    |v x B| = 1.20 10⁶ 0.65

     v xB = 0.78 10⁶

Let's replace and calculate

    2.30 = q 0.78 10⁶

    q = 2.3 / 0.78 106

    q = 2,95 10-6 C

4 0
3 years ago
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