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Olenka [21]
3 years ago
15

Do you think it is easier or harder to hammer a nail into a floorboard on Pluto than on Earth? How about the Sun? Explain.

Physics
1 answer:
Serggg [28]3 years ago
7 0

Explanation:

It would be easier to lift the  hammer, during the nailing, in Pluto than on earth but it would require more hammer jacks to drive the nail through the  floorboard. This is because the gravity on Pluto is weaker than on Earth. The additional acceleration of the hammer (due to gravity) would be lesser hence you would require to put in a bit more energy for the downforce of the hammer.

On the sun, it would be difficult to lift the hammer than here on earth. This is because the gravity of the sun is much greater than on earth. If you would manage to lift the hammer, the downforce of the hammer on the nail would have an added acceleration of the gravity of the sun hence the force of the hammer hitting the nail would be higher hence rapidly driving it through the floorboard.

Learn More:

For more on gravity check out;

brainly.com/question/9934704

brainly.com/question/3034702

#LearnWithBrainly

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An electrically neutral model airplane is flying in a horizontal circle on a 2.0-m guideline, which is nearly parallel to the gr
amm1812

Answer:

q=3.5*10^-4

Explanation:

<u>concept:</u>

The force acting on both charges is given by the coulomb law:

F=kq1q2/r^2

the centripetal force is given by:

Fc=mv^2/r

The kinetic energy is given by:

KE=1/2mv^2

<u>The tension force:</u>

<u><em>when the plane is uncharged </em></u>

T=mv^2/r

T=2(K.E)/r

T=2(50 J)/r

T=100/r

<u><em>when the plane is charged </em></u>

T+k*|q|^2/r^2=2(K.E)charged/r

100/r+k*|q|^2/r^2=2(53.5 J)/r

q=√(2r[53.5 J-50 J]/k)                                          √= square root on whole

q=√2(2)(53.5 J-50 J)/8.99*10^9

q=3.5*10^-4

5 0
2 years ago
An ideal spring hangs from the ceiling. A 1.95 kg mass is hung from the spring, stretching the spring a distance d=0.0865 m from
uranmaximum [27]

Answer:

kinetic energy = 0.1168 J

Explanation:

From Hooke's law, we know that ;

F = kx

k = F/x

We are given ;

Mass; m = 1.95 kg

Spring stretch; d = x = 0.0865

So, Force = mg = 1.95 × 9.81

k = 1.95 × 9.81/0.0865 = 221.15 N/m

Now, initial energy is;

E1 = mgL + ½k(x - L)²

Also, final energy; E2 = ½kx² + ½mv²

From conservation of energy, E1 = E2

Thus;

mgL + ½k(x - L)² = ½kx² + ½mv²

Making the kinetic energy ½mv² the subject, we have;

½mv² = mgL + ½k(x - L)² - ½kx²

We are given L=0.0325 m

Plugging other relevant values, we have ;

½mv² = (1.95 × 9.81 × 0.0325) + (½ × 221.15(0.0865 - 0.0325)² - ½(221.15 × 0.0865²)

½mv² = 0.62170875 + 0.3224367 - 0.82734979375

½mv² = 0.1168 J

7 0
3 years ago
In physics grade 10 number 8 in the pic how do we do it thanks in advance
Rom4ik [11]
Hope this helps you.

5 0
2 years ago
a car is moving with a constant speed of 20 meters per second.What total distance does the car travel in 2 minutes
N76 [4]
There are 120 seconds in two minutes, so to find the answer, you multiply 20 x 120 to get 2400 meters.
8 0
3 years ago
In what frame of reference would you be at rest while riding in a car?
Alexeev081 [22]

In the frame of reference of anybody in the car.

8 0
3 years ago
Read 2 more answers
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