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3 years ago

15

Do you think it is easier or harder to hammer a nail into a floorboard on Pluto than on Earth? How about the Sun? Explain.

1 answer:

Serggg [28]3 years ago

7 0

Explanation:

It would be easier to lift the hammer, during the nailing, in Pluto than on earth but it would require more hammer jacks to drive the nail through the floorboard. This is because the gravity on Pluto is weaker than on Earth. The additional acceleration of the hammer (due to gravity) would be lesser hence you would require to put in a bit more energy for the downforce of the hammer.

On the sun, it would be difficult to lift the hammer than here on earth. This is because the gravity of the sun is much greater than on earth. If you would manage to lift the hammer, the downforce of the hammer on the nail would have an added acceleration of the gravity of the sun hence the force of the hammer hitting the nail would be higher hence rapidly driving it through the floorboard.

Learn More:

For more on gravity check out;

brainly.com/question/9934704

brainly.com/question/3034702

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A charge Q is uniformly spread over one surface of a very large nonconducting square elastic sheet having sides of length d. At

Umnica [9.8K]

Answer:

Explanation:

Given

Charge Q is uniformly spread over large non-conducting Elastic sheet

Electric field due to non-conducting Elastic sheet

$E=\frac{\sigma }{2\epsilon }$

where $\sigma =$ surface charge density $=\frac{q}{d^2}$

$E=\frac{\frac{q}{d^2}}{2\epsilon }$

for side 2d Electric Field is given by

$E'=\frac{\frac{q}{2d^2}}{2\epsilon }$

$E'=\frac{1}{4}\times \frac{\frac{q}{d^2}}{2\epsilon }$

$E'=\frac{E}{4}$

8 0

3 years ago

How did Robert Whittaker change classification?

larisa [96]

He reorganized life into five kingdoms

7 0

2 years ago

Read 2 more answers

An object has a mass of 5.20g. The mass of the object in kg is

vampirchik [111]

Answer:

0.0520kg

Explanation:

divide by 1000

8 0

3 years ago

A bullet with a mass m b = 11.5 g is fired into a block of wood at velocity v b = 249 m/s. The block is attached to a spring tha

Ostrovityanka [42]

Answer:

0.358Kg

Explanation:

The potential energy in the spring at full compression = the initial kinetic energy of the bullet/block system

0.5Ke^2 = 0.5Mv^2

0.5(205)(0.35)^2 = 12.56 J = 0.5(M + 0.0115)v^2

Using conservation of momentum between the bullet and the block

0.0115(265) = (M + 0.0115)v

3.0475 = (M + 0.0115)v

v = 3.0475/(M + 0.0115)

plugging into Energy equation

12.56 = 0.5(M + 0.0115)(3.0475)^2/(M + 0.0115)^2

12.56 = 0.5 × 3.0475^2 / ( M + 0.0115 )

12.56 = 0.5 × 9.2872/ M + 0.0115

12.56 = 4.6436/ M + 0.0115

12.56 ( M + 0.0115 ) = 4.6436

12.56M + 0.1444 = 4.6436

12.56M = 4.6436 - 0.1444

12.56 M = 4.4992

M = 4.4992÷12.56

M = 0.358 Kg

4 0

3 years ago

1.- Se desea elevar un cuerpo de 1500kg utilizando una elevadora hidráulica de plato grande

kvv77 [185]

Answer:

181.48 N

Explanation:

Calculate the area :

Area = pi * r² ;

pi = 3.14 ; r1 = 90cm /100 = 0.9m ; r2 = 10/100 = 0.1m

Area 1, A1 = 3.14 * 0.1² = 0.0314 m²

Area 2, A2 = 3.14 * 0.9² = 2.5434 m²

Force, F = mass * acceleration due to gravity

F2 = 1500 * 9.8 = 14700 N

Force 1 / Area 1 = Force 2 / Area 2

Force 1 = (Force 2 / Area 2), * Area 1

Force 1 = (14700 / 2.5434) * 0.0314

Force = 5779.6650 * 0.0314

= 181.48 N

5 0

3 years ago