Question

A gas mixture contains 0.150 mol of oxygen (O2) gas, 0.419 mol of nitrogen (N2) gas. And 0.211 mol of argon (Ar) gas in a 0.250 L flask at 298 K. What is the total pressure of the mixture?

Answer 1

Hey There!:

Total number of moles of gases:

0.150 + 0.419 + 0.211 => 0.780 moles

Volume = 0.250 L

Temperature = 298 K

Using the ideal gas law:

p*V =  n*R*T , putting all the values we get :

p * 0.250 = 0.780 * 0.0821* 298

p* 0.250 = 19.083

p = 19.083 / 0.250

p = 76.3 atm

Hope That helps!