Ask question

Ask question

All categories

2 years ago

6

Explain what happens to the imidazole side chain of histidine in a buffer of pH 4.0 and at pH 10.2.

1 answer:

givi [52]2 years ago

4 0

Histidine, an essential amino acid, has as a positively charged imidazole functional group. The imidazole makes it a common participant in enzyme catalyzed reactions. The unprotonated imidazole is nucleophilic and can serve as a general base, while the protonated form can serve as a general acid.

You might be interested in

Can you help me please

melomori [17]

Answer:

I don't get yuh language kindly

6 0

3 years ago

Why is the time series useful as a management tool?

katrin [286]

Answer:

A)

Explanation:

It estimates the probability of extinction.

8 0

2 years ago

The eagle has landed was said when man landed on mars or on the moon

nekit [7.7K]

The moon, man has not been to mars yet

7 0

2 years ago

When balancing an equation, should you adjust the subscripts or the coefficients?

dimulka [17.4K]

Coefficients, you can’t change the subscripts but you can balance the equation by adding coefficients to both sides

3 0

3 years ago

Read 2 more answers

A 5.00-g sample of copper metal at 25.0 °C is heated by the addition of 133 J of energy. The final temperature of the copper is

vekshin1

<u>Answer:</u> The final temperature of the copper is 95°C.

<u>Explanation:</u>

To calculate the final temperature for the given amount of heat absorbed, we use the equation:

$Q= m\times c\times \Delta T$

Q = heat absorbed = +133 J (heat is added to the system)

m = mass of copper = 5.00 g

c = specific heat capacity of copper = 0.38 J/g ° C

$\Delta T={\text{Change in temperature}}=T_2-T_1$

$T_1=25^oC$

Putting values in above equation, we get:

$+133J=5.00g\times 0.38J/g^oC\times (T_2-25)\\\\T_2=95^oC$

Hence, the final temperature of the copper is 95°C.

3 0

2 years ago