Answer:
The mass of NH₄OH present in the solution is 8.085 g
Explanation:
Given;
molarity of NH₄OH = 6 M
density of NH₄OH = 0.960 g/mL
mass of NH₄OH = 37.0 grams
volume of NH₄OH = mass /density
= 37/0.96
= 38.54 mL
molarity = moles of solute / Liters of solution
moles of solute = molarity x Liters of solution
moles of solute = 6 x 38.54 x 10⁻³
moles of solute = 0.231 moles
Reacting mass = number of moles x molecular mass
Molecular mass of NH₄OH = 35 g/mol
Reacting mass = 0.231 mol x 35 g/mol
Reacting mass = 8.085 g
Therefore, the mass of NH₄OH present in the solution is 8.085 g
