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marusya05 [52]
4 years ago
12

Which best describes the purpose of a controlled experiment?

Physics
1 answer:
maksim [4K]4 years ago
3 0
<span> to minimize the effects of variables other than the independent variable</span>
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-What can you say about the snowboarder’s kinetic energy as he moves?
Damm [24]

Answer:

  His kinetic energy increases, potential energy decreases

  The sum of kinetic and potential energy is a constant at any instant before he comes to rest.

Explanation:

  Snowboarder is starting from a height and moving to the down direction. As he moves down his velocity increases, we know that kinetic energy is given by the expression \frac{1}{2} mv^2, so as he moves his kinetic energy increases.

  When the snowboarder is starting his potential energy is maximum(Potential energy = mgh), as he comes down his potential energy decreases.

  Based on this we can conclude that the sum of potential energy and kinetic energy is a constant at any instant for a snowboarder before he comes to rest.

                             mgh+\frac{1}{2} mv^2= Constant

 

7 0
4 years ago
The magnetic field inside a 5.0-cm-diameter solenoid is 2.0 T and decreasing at 5.00 T/s. Part A) What is the electric field str
Veronika [31]

Answer:

(A). The electric field strength inside the solenoid at a point on the axis is zero.

(B). The electric field strength inside the solenoid at a point 1.50 cm from the axis is 3.75\times10^{-2}\ V/m.

Explanation:

Given that,

Magnetic field = 2.0 T

Diameter = 5.0 cm

Rate of decreasing in magnetic field = 5.00 T/s

(A). We need to calculate the electric field strength inside the solenoid at a point on the axis

Using formula of electric field inside the solenoid

E=\dfrac{r}{2}|\dfrac{dB}{dt}|

Electric field on the axis of the  solenoid

Here, r = 0

E=\dfrac{0}{2}\times5.00

E = 0

The electric field strength inside the solenoid at a point on the axis is zero.

(B). We need to calculate the electric field strength inside the solenoid at a point 1.50 cm from the axis

Using formula of electric field inside the solenoid

E=\dfrac{r}{2}|\dfrac{dB}{dt}|

E=\dfrac{1.50\times10^{-2}}{2}\times|5.00|

E=0.0375= 3.75\times10^{-2}\ V/m

Hence, (A). The electric field strength inside the solenoid at a point on the axis is zero.

(B). The electric field strength inside the solenoid at a point 1.50 cm from the axis is 3.75\times10^{-2}\ V/m.

4 0
4 years ago
Only two horizontal forces act on a 3.0 kg body that can move over a frictionless floor. one force is 9.0 n, acting due east, an
Zolol [24]
The first thing you should do for this case is to find the horizontal and vertical components of the forces acting on the body.
 We have then:
 Horizontal = 9-9.2cos (58) = 4.124742769 N.
 Vertical = 9.2sin (58) = 7.802042485 N
 Then, the resulting net force is:
 F = √ ((4.124742769) ^ 2 + (7.802042485) ^ 2) = 8.825268826 N
 Then by definition:
 F = m * a
 Clearing the acceleration:
 a = F / m
 a = (8.825268826) / (3.0) = 2.941756275 m / s ^ 2
 answer:
 The magnitude of the body's acceleration is
 2.941756275 m / s ^ 2
6 0
3 years ago
An automobile with a mass of 1232 kg accelerates at a rate of 2 m/s² in the forward direction. What is the net force acting on t
boyakko [2]
Based on Newton's second law:
Force = mass x acceleration

For this problem: we have the mass = 1232 kg and the acceleration = 2 m/s^2
So, just substitute with the givens in the above equation to calculate the force as follows:
Force = 1232 x 2 = 2464 Newtons
7 0
3 years ago
A person jumped off a cliff, what would happen?
Anastaziya [24]
Death would happen, hope this helped
8 0
3 years ago
Read 2 more answers
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