Frequency = (speed) / (wavelength) = 20 / 0.5 = 40 per second = 40 Hz.
Explanation:
Momentum = mass × velocity
p = (65 kg) (5 m/s)
p = 325 kg m/s
Answer:
Explanation:
Because the total energy available to the ball doesn't change whatsoever during its entire trip from the window to the ground,
TE = KE + PE which says that the total energy available to a system is equal to the kinetic energy of the system plus the potential energy, and that this value will not ever change (because energy cannot be created or destroyed. Sound familiar?) If the ball is being held still before it is dropped from some height off the ground, it is here that the total energy can be determined, and that total energy at this point is all potential, since the ball is not moving while someone is holding it and getting ready to drop it. The SECOND it starts to fall, the potential energy begins to be converted to kinetic. As the potential energy is losing value, the kinetic is gaining it at the same rate (again, energy doesn't just disappear; it has to go somewhere. Here, it goes from potential to kinetic a little at a time). When the ball finally hits the ground, or an INSTANT BEFORE it hits the ground, the potential energy is 0 because the height of something on the ground has a height of 0. At this instant, right before the ball hits the ground, is where the KE is the greatest. All the energy at that point has been converted from potential to kinetic.
Long story short, choice B is the one you want.
Answer:
D. The chemical energy stays the same; additional energy is produced as heat, light, and other applicable energies.
Hope this helps!
Answer:
in projectile motion at maximum height v = 0
we can use the suvat equation to find v(initial)
since in this case v(final) is 0
t = 2.4 seconds
we need to find v(initial) or u
v = u+at
u = v- at
in this case a = g (gravity) = -9.81
u = 0 - (-9.81 * 2.4)
u = 9.81 * 2.4
the negatives become positive sin it’s a double negative ( - - = +)
