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djverab [1.8K]
3 years ago
10

An athlete ran a distance of 100 meters in 9.83 Seconds What’s his average speed

Physics
1 answer:
trasher [3.6K]3 years ago
6 0

Answer:

10.1729399797mp/s

Explanation:

100m divided by 9.83s=

10.1729399797mp/s

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While painting the top of an antenna 275 m in height, a worker accidentally lets a 1.00 L water bottle fall from his lunchbox. T
Tom [10]

Answer:

The force of impact of the water bottle is F = 13,475 N

Explanation:

Given data,

The height of the antenna, h = 275 m

The mass of the 1 L water bottle, m = 1 kg

Let the bottle moves distance immediately after the impact is, d = 0.2 m

The force exerted by the bottle on the bushes at the ground is given by the formula,

                                   F = mgh / d

Substituting the values

                                   F = 1 x 9.8 x 275 / 0.2

                                      = 13,475 N

The value of the force of impact can be reduced by increasing the value of d, it is like the lowering the hand along with the motion of the ball to catch it thereby reduce the force of impact.

The force of impact of the water bottle is F = 13,475 N

8 0
3 years ago
During development, the cells in these organisms become specialized.
Y_Kistochka [10]

Answer:

A- multicellular

Explanation:

fertilized egg I think that is the answer

7 0
3 years ago
A 10-kg package drops from chute into a 25-kg cart with a velocity of 3 m/s. The cart is initially at rest and can roll freely w
amid [387]

Answer:

(a) the final velocity of the cart is 0.857 m/s

(b) the impulse experienced by the package is 21.43 kg.m/s

(c) the fraction of the initial energy lost is 0.71

Explanation:

Given;

mass of the package, m₁ = 10 kg

mass of the cart, m₂ = 25 kg

initial velocity of the package, u₁ = 3 m/s

initial velocity of the cart, u₂ = 0

let the final velocity of the cart = v

(a) Apply the principle of conservation of linear momentum to determine common final velocity for ineleastic collision;

m₁u₁  + m₂u₂ = v(m₁  +  m₂)

10 x 3   + 25 x 0   = v(10  +  25)

30  = 35v

v = 30 / 35

v = 0.857 m/s

(b) the impulse experienced by the package;

The impulse = change in momentum of the package

J = ΔP = m₁v - m₁u₁

J = m₁(v - u₁)

J = 10(0.857 - 3)

J = -21.43 kg.m/s

the magnitude of the impulse experienced by the package = 21.43 kg.m/s

(c)

the initial kinetic energy of the package is calculated as;

K.E_i = \frac{1}{2} mu_1^2\\\\K.E_i = \frac{1}{2} \times 10 \times (3)^2\\\\K.E_i = 45 \ J\\\\

the final kinetic energy of the package;

K.E_f = \frac{1}{2} (m_1 + m_2)v^2\\\\K.E_f = \frac{1}{2} \times (10 + 25) \times 0.857^2\\\\K.E_f = 12.85 \ J

the fraction of the initial energy lost;

= \frac{\Delta K.E}{K.E_i} = \frac{45 -12.85}{45} = 0.71

7 0
3 years ago
Where do mosquito lay eggs
MakcuM [25]
Their called rafts they lay them by surface of stagnant water
4 0
3 years ago
Read 2 more answers
Two children are riding on a merry-go-round that is rotating with a constant angular speed. Abbie is one meter from the center o
Ainat [17]

Answer:

  • <em>Abbie’s acceleration is (1/2) Zak’s acceleration.</em>

Explanation

1. <u>Data</u>:

a) ω = constant

b) Abbie: r₁ = 1 m

c) Zak: r₂ = 2 m

d) Ac₁ = ? Ac₂

2. <u>Formulae</u>

  • Ac = ω² r

3. <u>Solution</u>:

a) Abbie:

  • Ac₁ = ω² r₁  =  ω² (1m)

b) Zack:

  • Ac₂ = ω² r₂  = ω² (2m)

c) Divide Ac₁ / Ac₂

  • Ac₁ / Ac₂ =  ω² (1m) / [ω² (2m) ] = 1/2

⇒      Ac₁ = (1/2) Ac₂ = Ac₂ / 2 = 0.5 Ac₂

5 0
3 years ago
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