An athlete ran a distance of 100 meters in 9.83 Seconds<br> What’s his average speed

According to the law of multiple proportions, if 12 g of carbon combine with 16 g of oxygen to form co, the number of grams of c

Ludmilka [50]

The number of grams of carbon that combine with 16 g of oxygen in the formation of CO₂ is 6g.

When two elements combine to make more than one compound, the masses of one element combined with a fixed amount of another element are in the ratio of whole numbers, according to the law of multiple proportions.

When combined with oxygen, carbon can produce two different compounds. They are referred to as carbon dioxide (CO₂) and carbon monoxide (CO).

Carbon monoxide is formed by combining 12 g of carbon with 16 g of oxygen whereas Carbon dioxide is formed when 12 g of carbon reacts with 32 g of oxygen. The amount of carbon is fixed at 12 g in each case. The mass ratio of carbon monoxide to carbon dioxide is 16: 32, or 1: 2.

But in the given case, 16g of oxygen is reacting instead of 32g. Therefore, the number of grams of carbon reacting will be:

$\frac{12}{2}=6g$

Thus, 6g of carbon will react with 16g of oxygen to form carbon dioxide.

Read more about Law of Multiple Proportions:

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7 0

10 months ago

A green block of mass m slides to the right on a frictionless floor and collides elastically with a red block of mass M which is

Charra [1.4K]

Answer:

M is equal to m

Explanation:

In case we say that the green block's mass m is less than red block's mass M, then the green block would have bounced and moved back to the left instead of coming to rest. The other case where if mass of green block's mass m would have been greater than the red block's mass M, the green block would have kept moving to the right instead of coming to rest. After collision, the red block moves to the right because of exchange of velocities. Therefore, m=M since m comes to rest and M moves to the right

In any collision, as it is asumed that no external forces can act during the collision, momentum must be conserved.

So, if we call p₁ to the momentum before collision, and p₂ to momentum after it, taking into account the information above, we can write the following:

p₁ = mv₁ + M.0 = p₂ = m.0 + Mv₂ ⇒ mv₁ = Mv₂

From the question, we also know that it was an elastic collision.

In elastic collision, added to the momentum conservation, it must be conserved the kinetic energy also.

So, if we call k₁ to the kinetic energy prior the collision, and k₂ to the one after it, we can write the following:

k₁ = 1/2 m(v₁)² + 1/2 M.0 = k₂ = 1/2m.0 + 1/2M(v₂)² ⇒ m(v₁)² = M(v₂)²

Mathematically, the only way in which both equations be true, should be with v₁ = v₂, which is only possible if m=M too.

In this type of collision, it is said that the energy transfers from one mass to the other.

8 0

3 years ago

Which atom is most likely to accept the electrons to form from an ionic bond

Mekhanik [1.2K]

a nonmetal with the amount of valence electrons that will complete atom

5 0

3 years ago

Philosophy is not considered science because it lacks:

dimulka [17.4K]

I think ans is experimentation because logic and writing is important in philosophy

6 0

3 years ago

Read 2 more answers

A block and tackle pulley system of 6 pulley uses 300N to overcome 1200N.find efficiency

Fittoniya [83]

Answer:

66.7%

Explanation:

There are 6 pulleys, so the mechanical advantage is 6.

The theoretical force needed to overcome 1200 N is therefore:

1200 N / 6 = 200 N

The actual force is 300 N. So the efficiency is:

200 N / 300 N × 100% = 66.7%

4 0

3 years ago

An athlete ran a distance of 100 meters in 9.83 Seconds What’s his average speed