Answer:
The answer to your question is given below
Explanation:
BaCrO4(s) <=> Ba^2+(aq) + CrO4^2-(aq)
Ksp = [Ba^2+]^A [CrO4^2-]^B
From the equation above,
Ba^2+ and CrO4^2- has 1 coefficient each. Therefore, the Ksp is given as:
Ksp = [Ba^2+] [CrO4^2-]
A = 1
B = 1
Mg(OH)2 <=> Mg^2+(aq) + 2OH^-(aq)
Ksp = [Mg^2+]^D [OH^-]^E
From the above equation,
Mg^2+ has a coefficient of 1
OH^- has a coefficient of 2
Therefore, the Ksp can be written as:
Ksp = [Mg^2+] [OH^-]^2
D = 1
E = 2
SrF2(s) <=> Sr^2+(aq) + 2F^-(aq)
Ksp = [Sr^2+]^C [F^-]^D
From the equation above,
Sr^2+ has a coefficient of 1.
F^- has a coefficient of 2.
Ksp = [Sr^2+] [F^-]^2
C = 1
D = 2
Cu3(PO4)2(s) <=> 3Cu^2+(aq) + 2PO4^3-(aq)
Ksp = [Cu^2+]^F [PO4^3-]^G
From the equation above,
Cu^2+ has a coefficient of 3
PO4^3- has a coefficient of 2
Ksp = [Cu^2+]^3 [PO4^3-]^2
F = 3
G = 2
