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Snowcat [4.5K]
3 years ago
12

What property of water is most important for living things?

Chemistry
2 answers:
Bess [88]3 years ago
5 0

Answer:

Water has the unique ability to dissolve many polar and ionic substances. This is important to all living things because, as water travels through the water cycle, it takes many valuable nutrients along with it! Water has high heat capacity.

Explanation:

hichkok12 [17]3 years ago
4 0

Answer:

Water has the unique ability to dissolve many polar and ionic substances. This is important to all living things because, as water travels through the water cycle, it takes many valuable nutrients along with it! Water has high heat capacity.

Explanation:

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How many moles of carbon are there in a 0.70 g (3.5 carat) diamond?
maksim [4K]

Answer:

3.5 x 10^22 moles of carbon are there in a 0.70 g (3.5 carat) diamond.

Explanation:

In case of diamond, the number of atoms is the same as the number of molecules.

7 0
3 years ago
An electron that is in the highest energy level of an atom and determines the atom's chemical properties is called a(n)
ss7ja [257]
The answer is C: Valence electron
3 0
3 years ago
A particle that has a negative charge Electrons Protons Non-polarMolecule Neutrons
murzikaleks [220]
Electron 

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7 0
2 years ago
The density of whole milk 1.04 g per mL. What is the volume (in quarts) of 18.5 pounds of whole milk?
nadya68 [22]

The volume : 8,526 quarts

<h3>Further explanation</h3>

Given

The density of whole milk = 1.04 g/ml

mass = 18.5 pounds

Required

The volume

Solution

Conversion of mass

1 pound = 453,592 g

18.5 pounds = 8391,45 g

Density formula:

\large{\boxed {\bold {\rho~=~ \frac {m} {V}}}}.

Input the value :

V = m : ρ

V = 8391,45 g : 1.04 g/ml

V = 8068.7 ml

1 ml = 0,00105669 quarts

8068.7 ml =8,526 quarts

3 0
2 years ago
A scientist digs up sample of arctic ice that is 458,000 years old. He takes it to his lab and finds that it contains 1.675 gram
Fiesta28 [93]

Answer:

6.70 grams of krypton-81 was present when the ice first formed

Explanation:

Let use the below formula to find the amount of sample

N= N_0(\frac{1}{2})^n

where

n = \frac{t}{t_{\frac{1}{2}}}

here

t =  458,000 years

t_{\frac{1}{2}} = 229,000

\frac{t}{t_{\frac{1}{2}}} = \\frac{ 458,000}{229,000}

n = \frac{t}{t_{\frac{1}{2}}} = 2.000

Now substituting the values

1.675 = N_0(\frac{1}{2})^{2.000}}

1.675 = N_0\times (0.2500)

N_0= \frac{1.675}{0.2500}

N_0=6.70

3 0
2 years ago
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