Answer:
O Continental-continental convergent boundary
Explanation:
Hope it helps.
This is true, this isn't a question, it's a fact.
Answer:
Brainliest pls
Explanation:
1 mole of a substance contains Avagadro’s number of particles,
i.e. 6.023*10^23
By unitary method,
5 moles of oxygen contains 5 times the Avagadro’s number of particles
i.e. 5* (6.023*10^23) = 3.0115*10^24 number of particles.
Now, the further answer depends on what particles the question concentrates on.
If number of atoms are asked , the above answer must be multiplied by 2, because oxygen is a diatomic gas and each atom contributes to be a particle.
therefore, 5 moles of oxygen has 6.023*10^24 atoms.
If number of molecules asked, the above answer is directly written...
NH3(aq) + HCl(aq) ⇒ NH4Cl(aq) >>> (1)
∵ C = n/V; C= concentration, n= No. of moles, and V= volume (L)
∴ n = C*V, n(HCl) = 0.050*(50/1000) = 0.0025 moles
n(NH3) = 0.050*(50/1000) = 0.0025 moles
So, the limiting no. of moles is 0.0025 moles >>> (2)
∵ NH3 is weak base, and HCl is strong Acid (and have the same number of moles) >>> So, without any calculation we can notice that the formed salt (NH4Cl) is acidic salt and the pH is less than 7.
From (1) and (2), The no. of moles of NH4Cl is 0.0025 moles >>> (3)
∴ the concentration of [NH4Cl] = 0.0025 / (total volume per L)
= 0.0025 / ((50 + 50) / 1000) = 0.025 M
NH4+(aq) ⇔ NH3(aq) + H+(aq) >>> (4)
(0.025 - x) (x) (x) >>> (5)
∵ Ka = [NH3] [H+] / [NH4+] >>>> (6)
Ka = Kw / Kb, Kb = 1.8 * 10^-5 >>> (7)
∴ Ka = 10^-14 / 1.8*10^-5 = 5.56*10^-10 >>> (8)
From (4), (5), (7) and (8)
Ka = 5.56*10^-10 = (x * x) / (0.025-x) , we will assume that (0.025 - x) = 0.025
∴ x^2 = (5.56*10^-10)(0.025) = 139*10^-13
∴ x = 3.73*10^-6 = [H+]
∵ pH = - log [H+]
∴ pH = - log 3.73*10^-6 = 5.43