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serious [3.7K]
3 years ago
13

I need to explain how objects can have the same volume but different mass. Help??

Physics
1 answer:
kaheart [24]3 years ago
6 0
No problem, and you already know all about it.

Here are a few examples of same volume / different weight:

-- A bottle full of water is heavier than the same bottle when it's full of air.
-- Stones are heavier than styrofoam chunks the same size.
-- A bowl of meat loaf is heavier than a bowl of scrambled eggs.

In each example, two things have the same volume, but one weighs more than
the other.  I didn't say anything about mass yet, but that's easy:  As long as you
keep everything on Earth, more weight means more mass.

So how come, in each example, things with the same volume have different mass ?
This was your original question.

The answer is just the simple fact that there are millions of different substances, and
each different substance packs a different amount of mass into the same volume.

The amount of mass that a substance packs into a standard volume is called
the <em>density</em> of the substance.  Meat loaf is more dense than scrambled eggs.
Stone is more dense than styrofoam.  Water is more dense than air.  And <em>gold</em>
is 19 times as dense as water.  If you have a jar that holds a pound of water, and
you pour out the water and fill the jar with gold, the same jar holds 19 pounds of gold,
because the density of gold is 19 times the density of water.

The reason you were assigned to think about this question for homework is that
next time your Physics class meets, you'll start talking about <em>Density. </em><em /> And you're
all ready for it now.
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Increases

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Determine the elastic energy U stored in<br> the compressed spring.
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Answer:

Answer: The spring constant of the spring is k = 800 N/m, and the potential energy is U = 196 J. To find the distance, rearrange the equation: The equation to find the distance the spring has been compressed is therefore: The spring has been compressed 0.70 m, which resulted in an elastic potential energy of U = 196 J being stored.

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2 years ago
On your first day at work as an electrical technician, you are asked to determine the resistance per meter of a long piece of wi
Lostsunrise [7]

Answer:

0.06\Omega/m

Explanation:

Firstly, when you measure the voltage across the battery, you get the emf,

E = 13.0 V

In order to proceed we have to assume that the voltmeter offers no loading effect, which is a valid assumption since it has a very high resistance.

Secondly, the wires must be uniform. So the resistance per unit length is constant (say z). Now, even though the ammeter has very little resistance it cannot be ignored as it must be of comparable value/magnitude when compared to the wires. This is can seen in the two cases when currents were measured. Following Ohm's law and the resistance of a length of wire being proportional to it's length, we should have gotten half the current when measuring with the 40 m wire with respect to the 20 m wire (I=\frac{V}{R}). But this is not the case.

Let the resistance of the ammeter be r

Hence, using Ohm's law we get the following 2 equations:

\frac{13}{20z+r} =7.6   .......(1)

\frac{13}{40z+r} =4.5     ......(2)

Substituting the value of r from (2) in (1), we have,

13=152z+7.6\times\frac{13-180z}{4.5}

which simplifying gives us, z=0.0589\Omega/m\approx0.06\Omega/m (which is our required solution)

putting the value of z in either (1) or (2) gives us, r = 0.5325 \Omega

3 0
2 years ago
Three point charges lie in a straight line along the y-axis. a charge of q1 = -9.10 µc is at y = 6.30 m, and a charge of q2 = -7
inysia [295]

Answer:

 Electric field E = kQ/r^2  

Distance between charges = 6.30 - (-4.40) = 10.70m  

Say the neutral point, P, is a distance d from q1. This means it is a distance (10.70 - d) from q2.  

Field from q1 at P = k(-9.50x^10^-6) / d^2  

Field from q2 at P = k(-8.40x^10^-6) / (10.70-d)^2  

These fields are in opposite directions and are equal magnitudes if the resultant field = 0  

k(-9.50x^10^-6) / d^2 = k(-8.40x^10^-6) / (10.70-d)^2  

9.50 / d^2 =8.40 / (10.70-d)^2  

d^2 / (10.70-d)^2 = 9.50/8.40 = 1.131  

d/(10.70-d) = sqrt(1.1331) = 1.063  

d = 1.063 ((10.70-d)  

= 10.63 - 1.063d  

2.063d = 10.63  

d = 5.15m  

The y coordinate where field is zero is 6.30 - 5.15 = 1.15m

Explanation:

4 0
3 years ago
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