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Dafna11 [192]
2 years ago
6

NEWTONS SECOND LAW LAB REPORT

Physics
1 answer:
hram777 [196]2 years ago
8 0

Answer:

Newton's second law states that the acceleration of an object is directly related to the net force and inversely related to its mass. Acceleration of an object depends on two things, force and mass.

Explanation:

here this may help.

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Red light of wavelength 630 nm passes through two slits and then onto a screen that is 1.4 m from the slits. The center of the 3
VARVARA [1.3K]

Answer:

Part a)

f = 4.76 \times 10^{14} Hz

Part b)

d = 3.48 \times 10^{-4} m

Part c)

\theta = 0.311 degree

Explanation:

Part a)

As we know that the speed of light is given as

c = 3 \times 10^8 m/s

\lambda = 630 nm

now the frequency of the light is given as

f = \frac{c}{\lambda}

so we have

f = \frac{3 \times 10^8}{630 \times 10^{-9}}

f = 4.76 \times 10^{14} Hz

Part b)

Position of Nth maximum intensity on the screen is given as

y_n = \frac{n\lambda L}{d}

so here we know for 3rd order maximum intensity

y_3 = 0.76 cm

n = 3

L = 1.4 m

0.76 \times 10^{-2} = \frac{3(630 \times 10^{-9})(1.4)}{d}

d = 3.48 \times 10^{-4} m

Part c)

angle of third order maximum is given as

d sin\theta = 3 \lambda

3.48 \times 10^{-4} sin\theta = 3(630 \times 10^{-9})

\theta = 0.311 degree

8 0
2 years ago
A wire is wrapped multiple times around a galvanized or aluminum nail and then each end of the wire connected to a battery for s
galina1969 [7]
Its A The paper clip is repelled away from the nail because an electromagnetic field magnetized to the nail
6 0
3 years ago
Read 2 more answers
Cuanto es tres por dos más cinco<br>3 * 2 + 5 es igual ​
Simora [160]

Answer:

3×2+5=11

Explanation:

3×2+5=

6+5

11

4 0
2 years ago
A 35.0-kg child swings in a swing supported by two chains, each 3.02 m long. The tension in each chain at the lowest point is 41
n200080 [17]

Answer:

Explanation:

Total tension must support the weight of the child and provide the necessary centripetal force.

    2T = m(g + v²/R)

2(414) = 35.0(9.81 + v²/3.02)

  828 = 35.0(9.81 + v²/3.02)

23.65 = 9.81 + v²/3.02

13.847 = v²/3.02

 41.81 = v²

      v = 6.47 m/s

F = 2(414) = 828 N    (ignoring the weight of the chains and seat)

3 0
2 years ago
(a) what is the period of small oscillations for this pendulum if it is located in an elevator accelerating upward at 9.00 m/s2?
Vinvika [58]

If this pendulum is situated in an elevator that is moving upward at a speed of 9.00 m/s2, the period of its minor oscillations is 4.34s.

<h3>One oscillation is it a period?</h3>

Period is equal to the length of one oscillation.

T. T . The frequency is the number of oscillations that occur in one second.

<h3>Short answer: How long does a pendulum swing?</h3>

A simple pendulum's period is: The symbol "T" stands for the period of time needed by the pendulum to complete one complete oscillation. The length of a basic pendulum: It is described as the distance the pendulum moves away from equilibrium and toward one side.

Since the elevator's oscillations for this pendulum are situated there and it is climbing at a 9.0 mph,

use G = 9.8 + 9.0 = 18.8 m/s²

Period T=2π√(L/G)

T= 2π√(9/18.8)

T=4.34s

To know more about oscillation visit:-

brainly.com/question/29273618

#SPJ4

7 0
11 months ago
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