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Kitty [74]
3 years ago
12

PLEASE HELP ME SOMEONE

Physics
1 answer:
tensa zangetsu [6.8K]3 years ago
4 0
To convert<span> temperatures in degrees </span>Fahrenheit to Celsius<span>, subtract 32 and multiply by .5556 (or 5/9)
So your answer is D</span>
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An air conditioner operating between 93°F and 70°F is rated at 4000 Btu/h cooling capacity. Its coefficient of performance is 27
lana [24]

Answer:P_{in}=0.25\ Hp

Explanation:

Given

Operating temperatures are

T_L=70^{\circ}F\approx 294.261\ K

T_H=93^{\circ}F\approx 307\ K

COP is 27\% of Carnot refrigerator

COP_{carnot}=\dfrac{T_L}{T_H-T_L}

COP_{carnot}=\dfrac{294.261}{307-294.261}

COP_{carnot}=\dfrac{294.261}{12.74}

COP_{carnot}=23.09\approx 23.1

actual COP=0.27 \times COP_{carnot}

COP_{actual}=6.237

Also, COP=\dfrac{\text{Desired effect}}{\text{Power in}}

6.237=\frac{4000}{P_{in}}

P_{in}=\frac{4000}{6.237}=641.33\ Btu/h

P_{in}=0.25\ Hp

6 0
3 years ago
Human reaction times are worsened by alcohol. How much further (in feet) would a drunk driver's car travel before he hits the br
sweet-ann [11.9K]

Answer:

A drunk driver's car travel 49.13 ft further than a sober driver's car, before it hits the brakes

Explanation:

Distance covered by the car after application of brakes, until it stops can be found by using 3rd equation of motion:

2as = Vf² - Vi²

s = (Vf² - Vi²)/2a

where,  

Vf = Final Velocity of Car = 0 mi/h

Vi = Initial Velocity of Car = 50 mi/h

a = deceleration of car  

s = distance covered

Vf, Vi and a for both drivers is same as per the question. Therefore, distance covered by both car after application of brakes will also be same.

So, the difference in distance covered occurs before application of brakes during response time. Since, the car is in uniform speed before applying brakes. Therefore, following equation shall be used:

s = vt

FOR SOBER DRIVER:

v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s

t = 0.33 s

s = s₁

Therefore,

s₁ = (73.33 ft/s)(0.33 s)

s₁ = 24.2 ft

FOR DRUNK DRIVER:

v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s

t = 1 s

s = s₂

Therefore,

s₂ = (73.33 ft/s)(1 s)

s₂ = 73.33 ft

Now, the distance traveled by drunk driver's car further than sober driver's car is given by:

ΔS = s₂ - s₁

ΔS = 73.33 ft - 24.2 ft

<u>ΔS = 49.13 ft</u>

6 0
3 years ago
What are some problems associated with the introduction of an exotic species into an ecosystem?
vodomira [7]
People in public getting killed
5 0
3 years ago
Read 2 more answers
If it takes 200 joules of energy to lift a bucket of water 3 meters in 2 seconds, how much power would be required to do the sam
Harlamova29_29 [7]

200 joules of work energy are involved.  That's all we need to know to answer the question.  Once we know that 200 joules of work energy are involved, we don't care what was lifted, or how far, or how long it took, or how many people worked on it, or how much they were paid, or what was the distribution of their gender identities, or the ethnic diversity among the team. or what day each of them celebrates as their sabbath.  Any other information besides the 200 joules is only there to distract us, and see whether we're paying attention.

Power = (work or energy) / (time to do the work or move the energy)

Power = (200 joules) / (5 seconds)

<em>Power = 40 watts</em>

3 0
3 years ago
The demand equation for the Roland portable hairdryer is given as follows where x (measured in units of a hundred) is the quanti
lesya [120]

Answer:

Explanation:

The concept of elastic and inelastic demand is applied.

for an elastic demand, the elasticity must be greater than 1 and for an Inelastic demand, the elasticity must be less than 1.

The steps and appropriate calculation is as shown in the attached file.

6 0
3 years ago
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