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Kitty [74]
3 years ago
12

PLEASE HELP ME SOMEONE

Physics
1 answer:
tensa zangetsu [6.8K]3 years ago
4 0
To convert<span> temperatures in degrees </span>Fahrenheit to Celsius<span>, subtract 32 and multiply by .5556 (or 5/9)
So your answer is D</span>
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A cart traveling at 0.3 m/s collides with stationary object. After the collision, the cart rebounds in the opposite direction. T
miv72 [106K]

Answer:

C.   In the first collision has twice the momentum as when it stays still ( second colllions)

Explanation:

To see which statement is correct, it is best to solve the problem, the momentum is equal to the variation of the moment

     I = Δp = m vf - m v₀

     I = m (vf -v₀)

Case 1. In car bounces, the initial speed is 0.3 m / s, say that this direction is positive, when the magnitude of the speed bounces it remains constant, but its direction is reversed (vf = -0.3 m / s)

    I₁ = m (-0.3 - 0.3)

    I₁ = -0.6 m

Case 2. The expensive one that still after the crash so its speed is zero (vf = 0)

    I₂ = m (0 - 0.3)

    I₂ = -0.3 m

Let's calculate the relationship between the two impulses

     I₁ / I₂ = -0.6m / -0.3m

     I₂ / I₂ = 2

When it bounces it has twice the momentum as when it stays still

Now let's analyze the answers:

A.   False The momentum changes

B. False. The momentum is less in the second collision

C. True.  The momentum is double in this collision

D. False. Can be calculated, because the mass is the same throughout the exercise and is eliminated in the equations

E. False.  When they say bounces it implies the same speed with the opposite direction

4 0
3 years ago
A single atom of an element has 11 protons, 11 electrons, and 12 neutrons. Which element is it?
Anettt [7]
The sodium atom, Na, contains 11 protons, 11 electrons, and 13 neutrons.
6 0
2 years ago
Mercury is added to a cylindrical container to a depth d and then the rest of the cylinder is filled with water.
VARVARA [1.3K]

Answer:

0.05m

Explanation:

Density of water = ρ(w) = 1000 kg/ m³ ;  

Density of Mercury = ρ(m) = 13628.95 kg/ m³  

Total pressure at bottom of cylinder=1.1atm

Therefore, pressure due to water and mercury =1.1-1 =atm

0.1atm=10130pa

The pressure at the bottom is given by,

ρ(w) x g[0.4 - d] + ρ(m) x g x d  = 10130

1000 x 9.8[0.4 - d] + 13628.95 x 9.8 d = 10130

3924 - 9810d + 133416d= 10130

123606d= 6206

d= 6202/123606

d= 0.05m

Depth of mercury alone =  d = 0.05m

8 0
3 years ago
Read 2 more answers
where F is the magnitude of the gravitational attraction on either body, m1 and m2 are the masses of the bodies, r is the distan
zavuch27 [327]

                              Force  =  G  ·  m₁  ·  m₂   /   r²

In all SI units . . .

                        [ newton ]  =  [ G ] · [kg] · [kg] / [meter²]

But 'newton' is  kg-m / s²
So the formula says

                                  [ kg-m / s² ]  =  [ G ] · [kg] · [kg] / [meter²]

Divide each side
by  kg² :                    kg-m / s²-kg²  =  [ G ]  /  meter²

Multiply each side
by  meter² :              kg-m-m² / s²-kg²  =  G

Cancel 'kg' from
top and bottom:            m-m² / s²-kg  =  G

Clean it up:                 <span>   [ G ]  =  m³ / kg - s²      <==

Check:
Look up "Gravitational constant" on-line:
</span>Gravitational constant =  6.67408 × 10-11 m³ kg⁻¹ s⁻²   <==          yay !<span />
                        
8 0
2 years ago
What is the movement of the ocean floor called"?
Sonja [21]
The answer to your question is seafloor spreading.
8 0
2 years ago
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