Answer:
V = 2.14 m/s
Explanation:
Given,
The mass of the bullet, m = 12.7 g
= 0.0127 Kg
The velocity of the bullet, v = 430 m/s
The weight of the rifle, w = 25 N
∴ The mass of the rifle, M = 25/9.8
= 2.55 Kg
According to the law of conservation of momentum,
MV + mv = 0
Therefore, the recoil velocity of the gun
V = -mv/M
Substituting the given values in the above equation
V = -0.0127 x 430 /2.55
= -2.14 m/s
The negative sign indicates the direction of V with respect to v.
Hence, the recoil velocity of the gun is, V = 2.14 m/s
