Answer:
The ratio of the man's kinetic energy to that of the woman's kinetic energy is 0.629.
Explanation:
Given;
weight of the man, W = 700 N
Weight of the woman, W = 440 N
momentum is given by;

Kinetic energy of the man;

Momentum of the man is calculated as;

The kinetic energy of the woman is given by;

The momentum of the woman is given;

Since, momentum of the man = momentum of the woman


mass of the mas = 700 / 9.8 = 71.429
mass of the woman is = 440 / 9.8 = 44.898

Therefore, the ratio of the man's kinetic energy to that of the woman's kinetic energy is 0.629.
Answer:
0.4 s
Explanation:
The time that the ball is in the air can be found with the next formula:

where
is the initial velocity of the ball, in this case:

β is the angle: β = 29.0°
And g is the acceleration of gravity: 
Replacing all the values to find t, we have:

Thus, the ball is 0.4s in the air.
Answer:
-0.8 m/s²
Explanation:
Acceleration is the slope of a velocity vs. time graph.
a = Δv / Δt
a = (0 m/s − 12 m/s) / (15 s − 0 s)
a = -0.8 m/s²
Answer:
700,000g
Explanation:
1kg = 1000 Grams (or any kg x 1000)