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Schach [20]
3 years ago
13

Which instrument is not used to measure air pressure

Physics
1 answer:
Virty [35]3 years ago
5 0
It would be b. anemometer. it measures the speed of wind or any current of gas.
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What happens to the reaction 2 N O 2 in equilibrium with N 2 O 4 plus 57.3 kilojoules when the temperature of the reaction is in
Burka [1]

Answer:

More reactant forms.

Explanation:

Given reaction is,

2NO_{2}⇒N_{2} O_{4}+57.3 KiloJoulesper mole

This is an Exothermic Reaction,(ΔE=-57.3KJper mole)

We know the equilibrium point of all Exothermic reactions moves leftward and more reactant is formed at the equilibrium.

<u>Reason:</u>

As heat is being produced in the reaction the additional heat(57.3KJpermole) can be <u>thought of as a product</u> of the reaction.

So,if you increase the temperature ,you provide heat energy,

(in other words heat energy is given) and hence the concentration of the products increases.

So, with respect to LeChateliers Principle,

As the concentration of products is increased by external means,more of the reactants are produced at the equilibrium of the reaction.

Therefore amount of reactants increases as <u>more reactant forms.</u>

3 0
2 years ago
Read 2 more answers
A student walks (2.9±0.1)m, stops and then walks another (3.9 ±0.2)m in the same directionWith the given uncertainties, what is
Anika [276]

Answer:

The smallest distance the student that the student could be possibly be from the starting point is 6.5 meters.

Explanation:

For 2 quantities A and B represented as

A\pm \Delta A and B\pm \Delta B

The sum is represented as

Sum=(A+B)\pm (\Delta A+\Delta B)

For the the values given to us the sum is calculated as

Sum=(2.9+3.9)\pm (0.1+0.2)

Sum=6.8\pm 0.3

Now the since the uncertainity inthe sum is \pm 0.3

The closest possible distance at which the student can be is obtained by taking the negative sign in the uncertainity

Thus closest distance equals 6.8-0.3=6.5meters

3 0
3 years ago
If I walk 15 minutes miles north and then 20 miles South:
Anna71 [15]

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Kinematics.

1.) Distance travelled = 15+20 = 35 miles.

Ai the total distance covered is 35 miles.

2.) Displacement is the shortest distance from the initial point to the final point.

here it's ==> 20-15 = 5 miles

hence, displacement = 5 miles

6 0
2 years ago
By method of dimension show that the following equation are homogenous.
il63 [147K]

Answer:

Proof in explanataion

Explanation:

The basic dimensions are as follows:

MASS = M

LENGTH = L

TIME = T

i)

Given equation is:

H = \frac{u^2Sin^2\phi}{2g}

where,

H = height (meters)

u = speed (m/s)

g = acceleration due to gravity (m/s²)

Sin Ф = constant (no unit)

So there dimensions will be:

H = [L]

u = [LT⁻¹]

g = [LT⁻²]

Sin Ф = no dimension

Therefore,

[L] = \frac{[LT^{-1}]^2}{[LT^{-2}]}\\\\\ [L] = [L^{(2-1)}T^{(-2+2)}]

<u>[L] = [L]</u>

Hence, the equation is proven to be homogenous.

ii)

F = \frac{Gm_1m_2}{r^2}\\\\

where,

F = Force = Newton = kg.m/s² = [MLT⁻²]

G = Gravitational Constant = N.m²/kg² = (kg.m/s²)m²/kg² = m³/kg.s²

G = [M⁻¹L³T⁻²]

m₁ = m₂ = mass = kg = [M]

r = distance = m = [L]

Therefore,

[MLT^{-2}] = \frac{[M^{-1}L^{3}T^{-2}][M][M]}{[L]^2}\\\\\ [MLT^{-2}] = [M^{(-1+1+1)}L^{(3-2)}T^{-2}]\\\\

<u>[MLT⁻²] = [MLT⁻²]</u>

Hence, the equation is proven to be homogenous.

8 0
2 years ago
What are the values of the missing forces<br><br> A.<br> B.
g100num [7]

Answer:

X and Y forces must balance:

Fb = 150 N

Fa = 75 N

3 0
2 years ago
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