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3 years ago

Which instrument is not used to measure air pressure

Physics

1 answer:

Virty [35]3 years ago

5 0

It would be b. anemometer. it measures the speed of wind or any current of gas.

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A set of charged plates 0.00262 m apart has an electric field of 155 N/C between them. What is the potential difference between

mylen [45]

Answer: The potential difference between the plates = 0.4061V

Explanation:

Given that the

Electric field strength E = 155 N/C

Distance d = 0.00262 m

From the definition of electric field strength, is the ratio of potential difference V to the distance between the plates. That is

E = V/d

Substitute E and d into the above formula

155 = V/0.00262

Cross multiply

V = 155 × 0.00262

V = 0.4061 V

The potential difference between the plates is 0.4061 V

5 0

3 years ago

A particle moves along a straight line. Its position at any instant is given by x = 32t− 38t^3/3 where x is in metre and t in se

Rudik [331]

Answer:

The acceleration of the object is -69.78 m/s²

Explanation:

Given;

postion of the particle:

$x = 32t - 38\frac{t^3}{3} \\\\$

The velocity of the particle is calculated as the change in the position of the particle with time;

$v = \frac{dx}{dt} = 32 - 38t^2\\\\when \ the \ particle \ is \ at \ rest, \ v = 0\\\\32-38t^2 = 0\\\\38t^2 = 32\\\\t^2 = \frac{32}{38} \\\\t = \sqrt{\frac{32}{38} } \\\\t = 0.918 \ s$

Acceleration is the change in velocity with time;

$a = \frac{dv}{dt} = -76t\\\\recall , \ t = 0.918 \ s\\\\a = -76(0.918)\\\\a = -69.78 \ m/s^2$

4 0

3 years ago

I need help please!!

quester [9]

Answer:

i need help please
need i help please

6 0

2 years ago

In loading a lorry, a man lifts boxes each of weight 100N through a height of 1.5m.

liq [111]

Answer:

The amount of work done in order to lift the box is $150\ Joule$

Explanation:

Given the weight of each box is $100N$

And the man lifts boxes at a height of $1.5m$

We need to find the amount of work done.

The amount of work done is the product of applied force $F$ that causes the displacement $d$ .

In our problem force is $100N$ and displacement is $1.5m$ .

Now, work done

$=force\times displacement\\=100\times1.5\\=150\ Joule$

So, the amount of work done in order to lift the box is $150\ Joule$

5 0

3 years ago

a bowling ball of mass 7.3 kg and radius 9.6 cm rolls without slipping down a lane at 3.1 m/s . part a calculate its total kinet

erma4kov [3.2K]

49 J is the total kinetic energy. If a bowling ball of mass 7.3 kg and radius 9.6 cm rolls without slipping down a lane at 3.1 m/s. Kinetic energy is the energy an bowling ball has because of its motion.

Given: m = 7.3 Kg ; r = 9.4 cm = 0.094 m ; v = 3.1 m

Now total kinetic energy in this case is given by KE = Kinetic energy due to rotation + Kinetic energy due to translation

i,e KE = 1/2*m*v2 + 1/2*I*ω2 where I is the moment of inertia of the bowling ball about it's center and ω is the angular velocity

Now for pure rotation (without slipping) v = rω

also for the ball (solid sphere) I = 2/5*m*r2

Hence our kinetic energy becomes

KE = 1/2*m*v2 + 1/5*m*v2 = 7/10*m*v2

so KE = 0.7*7.3*(3.1)2 = 49.10 J = 49 J

Learn more about kinetic energy here

brainly.com/question/12669551

#SPJ4

5 0

1 year ago