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OlgaM077 [116]
3 years ago
7

A man stands on a scale in an elevator as shown here. the force of his weight when the elevator is still is fg downward. suppose

the elevator's acceleration downward is 1/4 g. the weight of the man, fs, is what
Physics
1 answer:
Sever21 [200]3 years ago
7 0
When the elevator moves downward, the man weighs less because of the inertia.
Force of Weight:Fg=m×g
Fs=m×g-m×1/4g=m×(g-1/4g)=m×3/4g
If He Went Up you would have to add 1/4g
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Consider a double-slit with a distance between the slits of 0.04 mm and slit width of 0.01 mm. Suppose the screen is a distance
scZoUnD [109]

Answer:

The distance between the places where the intensity is zero due to the double slit effect is 15 mm.

Explanation:

Given that,

Distance between the slits = 0.04 mm

Width = 0.01 mm

Distance between the slits and screen = 1 m

Wavelength = 600 nm

We need to calculate the distance between the places where the intensity is zero due to the double slit effect

For constructive fringe

First minima from center

x_{1}=\dfrac{\lambda D}{2d}

Second minima from center

x_{2}=\dfrac{3\lambda D}{2d}

The distance between the places where the intensity is zero due to the double slit effect

\Delta x_{d}=x_{2}-x_{1}

\Delta x_{d}=\dfrac{3\lambda D}{2d}-\dfrac{\lambda D}{2d}

\Delta x_{d}=\dfrac{\lambda D}{d}

Put the value into the formula

\Delta x_{d}=\dfrac{600\times10^{-9}\times1}{0.04\times10^{-3}}

\Delta x_{d}=0.015 =15\times10^{-3}\ m

\Delta x_{d}=15\ mm

Hence, The distance between the places where the intensity is zero due to the double slit effect is 15 mm.

8 0
3 years ago
The tape in a videotape cassette has a total
Softa [21]

Answer:

1.37 rad/s

Explanation:

Given:

Total length of the tape is, d= 297 m

Total time of run is, t = 2.1 hours

We know, 1 hour = 3600 s

So, 2.1 hours = 2.1 × 3600 = 7560 s

So, total time of run is, t= 7560 s

Inner radius is, r = 10\ mm = 0.01\ m


Outer radius is, R = 47\ mm = 0.047\ m


Now, linear speed of the tape is, v =\frac{d}{t}=\frac{297}{7560}=0.039\ m/s


Let the same angular speed be \omega.

Now, average radius of the reel is given as the sum of the two radii divided by 2.

So, average radius is, R_{avg}=\frac{R+r}{2}=\frac{0.047+0.01}{2}=\frac{0.057}{2}=0.0285\ m


Now, common angular speed is given as the ratio of linear speed and average radius of the tape. So,

\omega=\dfrac{v}{R_{avg}}\\\\\\\omega=\dfrac{0.039}{0.0285}\\\\\\\omega=1.37\ rad/s


Therefore, the common angular speed of the reels is 1.37 rad/s.

5 0
3 years ago
plastic bags have replaced for the packing of the most materials. give these advantages and two disadvantages of using plastic o
Nezavi [6.7K]
It is waterproof and more durable
5 0
3 years ago
Match the following moves to the correct total distance and displacement of the moves.
MAVERICK [17]
A. Move 2 m east and then 12 m east; displacement is 14 m east and the distance is 14 m
B. Move 10 m east and then 12 m west, the displacement is 2 m west and the distance is 22 m.
C. Move 8 m west and then 16 m east; the displacement is 8 m east and the distance is 24 m
D. Move 12 m west and then 8 m east; the displacement is 4 m and the distance is 20 m
5 0
3 years ago
A motorbike accelerates from 15m/s to 25m/s in 15 seconds.
RSB [31]

distance traveled by a uniformly accelerated bike is given as

d = \frac{v_f + v_i}{2} (t)

here we know that

v_f = 25 m/s

v_i = 15 m/s

t = 15 s

now we will have from above equation

d = \frac{15 + 25}{2} (15)

d = 20 (15) = 300 m

so it will cover the total distance of 300 m

5 0
3 years ago
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