Answer:
<em>D) The force F is perpendicular (normal) to both velocity V and magnetic field B.</em>
Explanation:
When a charged particle enters a magnetic field, it experiences a force which changes its direction of travel. The direction of motion of the charged particle, the magnetic field direction, and the direction of the force, are all perpendicular to one another. According to Lorentz right hand rule, hold the right hand parallel to the ground, with the palm facing up, and the thumb held out at right angle to the other fingers. If the direction of the other fingers represents the magnetic field line and direction, and the thumb represents the direction of motion of a positively charged particle, then, the palm will push up in the direction of the force. For a negatively charged particle, the force will push down in the direction of the back of the hand.
Answer:
The net force exerted by the two charges is 10.97 x 10⁻⁵ N along negative x-direction.
Explanation:
K=1/4πϵ0, where ϵ0=8.854×10−12C2
K = 9x10⁹
The electric force on point charge q₃ due to charge q₂ is
F₃₂ = kq₃q₂ / (1.245)²
= (9x10⁹ * 49.5x10⁻⁹ * 30.5x10⁻⁹) / (1.245)²
= 13,587.75 x 10⁻⁹ / 1.55
= 8.76629 x 10⁻⁵ N
The electric force on point charge q₃ due to charge q₁ is
F₃₁ = kq₃q₁ / (1.695 - 1.245)²
= (9x10⁹ * 49.5x10⁻⁹ * 10.0x10⁻⁹) / 0.2025
= 2.2000 x 10⁻⁵ N
The net electric force on point charge q₃ is
F₃ = -F₃₁ - F₃₂
= - 8.76629 x 10⁻⁵ N - 2.2000 x 10⁻⁵ N
= 10.97 x 10⁻⁵ N along negative x-direction
Explanation:
For projectile motion, use constant acceleration equation:
Δx = v₀ t + ½ at²
where Δx is the displacement,
v₀ is the initial velocity,
a is the acceleration,
and t is time.
Both objects are projected upward with velocity u. The second object is thrown after a time t₀.
For the first object:
Δx = u t + ½ (-g) t²
Δx = u t − ½g t²
For the second object:
Δx = u (t−t₀) + ½ (-g) (t−t₀)²
Δx = u (t−t₀) − ½g (t−t₀)²
Assuming the objects meet, the displacements will be equal:
u t − ½g t² = u (t−t₀) − ½g (t−t₀)²
u t − ½g t² = u (t−t₀) − ½g (t² − 2tt₀ + t₀²)
u t − ½g t² = u t − u t₀ − ½g t² + g tt₀ − ½g t₀²
0 = -u t₀ + g tt₀ − ½g t₀²
0 = -u + g t − ½g t₀
g t = u + ½g t₀
t = u/g + t₀/2
Answer:
they carry a heavier load
Explanation:
Answer:
speed = 1.24 × 10⁸m/s
frequency = 4.74 × 10¹⁴Hz
wavelength = 262nm
Explanation:
the speed of the helium-neon light in zircon is given by,
v = c / n
c = 3 × 10⁸m/s is the speed of light in vacuum (and in air)
n = 2.419 is the refractive index of diamond
v = 3 × 10⁸ / 2.419
= 1.24 × 10⁸m/s
(b) Frequency
The wavelength of the light in air is:
λ₀ = 632.8 × 10⁻⁹
The frequency of the light does not depend on the medium, so it is equal in air and in diamond. Therefore, we can calculate the frequency by using the speed of light in air and the wavelength in air:
f₀ = c / λ₀
= 3 × 10⁸ / 632.8 × 10⁻⁹
= 4.74 × 10¹⁴Hz
and the frequency of the light indiamond is the same:
f¹ = f₀ = 4.74 × 10¹⁴Hz
(c) Wavelength
To calculate the wavelength of the light in daimond, we can use the relationship between speed of light in diamond and frequency:
λ¹ = v / f¹
= 1.24 × 10⁸ / 4.74 × 10¹⁴
= 2.62 × 10⁻⁷m
= 262nm
