The number can be used to get rid of all fractions is 12
<h3>What number can be used to get rid of all fractions?</h3>
The equation is given as:
6 - 3/4x + 1/3 = 1/2x + 5
The denominator of the fractions are:
4, 3 and 2
The LCM of 4, 3 and 2 is 12
So, we have:
12 * [6 - 3/4x + 1/3] = 12 * [1/2x + 5]
Evaluate the products
72 - 9x + 12 = 6x + 60
Hence, the number can be used to get rid of all fractions is 12
Read more about fractions at:
brainly.com/question/11562149
#SPJ1
Answer:
Pr(all will survive in one year) = 0.35 to 2 decimal places
Pr(at least 8 will survive) = 0.39 to 2 decimal places.
Step-by-step explanation:
Probability of a tree surviving one year is 0.9. While not surviving probability is 1 - 0.9 = 0.1
This is obtained from the 90℅ surviving rate for one year planted by the landscaping firm.
Probability that if 10 trees are planted, all will survive for one year is:
0.9x0.9x0.9x0.9x0.9x0.9x0.9x0.9x0.9x0.9 = 0.9^10 = 0.349
Probability that at least 8 will survive in one year can be expressed as
8 survived x 2 not survived +(or) 9 survived x 1 not survived +(or) 10 survived
= [(0.9^8)x(0.1^2) + (0.9^9)x(0.1^1) + (0.9^10)] = 0.391
Step-by-step explanation:
To find a percent from a decimal, you multiply the decimal by 100. So, the answer would be A.
Answer:
i do not know
Step-by-step explanation:
For proof of 3 divisibility, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.
<h3>
Integers divisible by 3</h3>
The proof for divisibility of 3 implies that an integer is divisible by 3 if the sum of the digits is a multiple of 3.
<h3>Proof for the divisibility</h3>
111 = 1 + 1 + 1 = 3 (the sum is multiple of 3 = 3 x 1) (111/3 = 37)
222 = 2 + 2 + 2 = 6 (the sum is multiple of 3 = 3 x 2) (222/3 = 74)
213 = 2 + 1 + 3 = 6 ( (the sum is multiple of 3 = 3 x 2) (213/3 = 71)
27 = 2 + 7 = 9 (the sum is multiple of 3 = 3 x 3) (27/3 = 9)
Thus, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.
Learn more about divisibility here: brainly.com/question/9462805
#SPJ1
