Answer:
X-ray Telescope
Explanation:
X-ray Telescope which can be either hard or soft is an instrument on an orbiting satellite that would detect the flare first.
This is because X-ray Telescope is technically designed to detect and determine X-rays or radio and optical emissions from flares, from places or points beyond Earth's atmosphere.
Vo = 89 m/s
angle: 40°
=> Vox = Vo * cos 40° = 89 * cos 40°
=> Voy = Vo. sin 40° = 89 * sin 40°
x-movement: uniform => x =Vox * t = 89*cos(40)*t
x = 300 m => t = 300m / [89m/s*cos(40) = 4.4 s
y-movement: uniformly accelerated => y = Voy * t - g*t^2 /2
y = 89m/s * sin(40) * (4.4s) - 9.m/s^2 * (4.4)^2 / 2 = 156.9 m = height the ball hits the wall.
To solve this problem we will apply the definition of the ideal gas equation, where we will clear the density variable. In turn, the specific volume is the inverse of the density, so once the first term has been completed, we will simply proceed to divide it by 1. According to the definition of 1 atmosphere, this is equivalent in the English system to
The ideal gas equation said us that,
PV = nRT
Here,
P = pressure
V = Volume
R = Gas ideal constant
T = Temperature
n = Amount of substance (at this case the mass)
Then
The amount of substance per volume is the density, then
Replacing with our values,
Finally the specific volume would be
Answer:
The answer is 24cm
Explanation:
This problem bothers on the curved mirrors, a concave type
Given data
Object height h= 5cm
Object distance = 12cm
Focal length f=24cm
Let the image distance be v=?
Applying the formula we have
1/v +1/u= 1/f
Substituting our given data
1/v+1/12=1/24
1/v=1/24-1/12
1/v=1-2/24
1/v=-1/24
v= - 24cm
This implies that the image is on the same side as the object and it is real
Answer: The incident ray and the reflected ray and the normal will be parallel to each other.
Explanation:
The normal is perpendicular to the surface of the mirror or the reflective surface.
According to the law of reflection which state that:
The angle of incidence is always equal to the angle of reflection on a smooth surface.
If a light ray is incident on a reflective surface along the normal. The angle of incidence will be at 90 degrees which will be perpendicular to the surface of the mirror, the reflected ray will bounce back likewise at the same angle which will be perpendicular to the reflective surface.
Both the incident ray and the reflected ray and the normal will be parallel to each other.
