A. A car comes equipped with side airbags. I don't know how I'm supposed to show work but that's the answer
Make a puzzle and each puzzle piece represent a state
Answer:
Explanation:
Given that
F=ax^3/2. a is a constant
The force does a work of
W=2.01KJ from x=0 to x=15.2m
We need to find a
Work is give as,
W=∫F.ds
But this is in x direction only then,
W=∫Fdx. from x=0 to x=15.2m
W=∫ax^3/2dx from x=0 to x=15.2m
W=ax^(3/2+1)/(3/2+1).
W=ax^(5/2)/5/2
W=ax^(2/5)/2.5 from x=0 to x=15.2m
Cross multiply
2.5W=ax^2.5. from x=0 to x=15.2m
2.5W= a (15.2^2.5-0)
W=2.01KJ=2010J
2.5×2010=a×900.76
Therefore,
a=5.56
The horizontal motion of a launched projectile affects its vertical motion is false
Answer: False
<u>Explanation:
</u>
As the trajectory falls on a plane, all the components like displacement, velocity can be classified in two components termed as horizontal and vertical component.
In a projectile motion, the horizontal components of displacement and velocity remains constant and there is change only in the vertical component of displacement and velocity.
Both components are not dependent to each other. So, the horizontal motions of a launched projectile does not affect its vertical motion.
