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ira [324]
3 years ago
10

What do repeated trails in an experiment allow scientists to do?

Physics
1 answer:
fredd [130]3 years ago
3 0

Answer:

Explanation:

When we do multiple trials of the same experiment, we can make sure that our results are consistent and not altered by random events. Multiple trials can be done at one time. If we were testing a new fertilizer, we could test it on lots of individual plants at the same time.

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17. (16 pts) You set up a two-slit experiment with a laser that produces light with a
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when the two waves interfere with eachother to make a dark spot the periodic difference of the two waves is π . the wave length for 2π is 600nm

. ie. for π difference it is 300nm

4 0
4 years ago
Which element is most likely to have an oxidation number of +3?
Marina86 [1]

Answer:

A different answer to this is AI

Explanation:

4 0
3 years ago
If the ice cube absorbs heat, then, heat
Rashid [163]

Answer:

<h2><em>I have no idea what any of that means </em>:'(</h2>

Explanation:

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5 0
3 years ago
3. The largest asteroid in the solar system is 1 Ceres. It has a mass of 9.3835
Ira Lisetskai [31]

Answer:

2.8351×10^7 N/kg

Explanation:

We know that,

W = mg -------(1)

where W = weight, m = mass, g = gravitational acceleration

Also from Newton's law of gravitation we know that,

F = GMm/r²

Where,

F = gravitational force,

G = universal gravitational constant

M,m = masses of object under gravitational influence

r = distance between the two center of masses.

Here we get

F = (Gm/r²)M -------(2)

From 1 and 2

The acceleration due to gravity = gravitational field intensity

So if you consider the gravitational field intensity at the surface of the asteroid,it is equal to the acceleration due to gravity at the same place.

So we get,

g = (6.67×10^-11)×9.3835×10^20/(47²) = 2.8351×10^7 N/kg

3 0
4 years ago
A spherical balloon is inflated with gas at the rate of 500 cubic centimeters per minute. How fast is the radius of the balloon
Nookie1986 [14]

Answer:

<h2>0.245cm/min</h2>

Explanation:

The volume of the spherical balloon is expressed as V = 4/3πr³ where r is the radius of the spherical balloon. If the spherical balloon is inflated with gas at the rate of 500 cubic centimetres per minute then dV/dt = 500cm³.

Using chain rule to express dV/dt;

dV/dt = dV/dr*dr/dt

dr/dt is the rate at which the radius of the gallon is increasing.

From the formula, dV/dr = 3(4/3πr^3-1))

dV/dr = 4πr²

dV/dt = 4πr² *dr/dt

500 =  4πr² *dr/dt

If radius r = 40;

500 = 4π(40)² *dr/dt

500 = 6400π*dr/dt

dr/dt = 500/6400π

dr/dt = 5/64π

dr/dt  = 0.245cm/min

Hence, the radius of the balloon is increasing at the rate of 0.245cm/min

8 0
3 years ago
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