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3 years ago

The ossicles (the three tiny bones in the middle ear) are responsible for __________.

Physics

2 answers:

tiny-mole [99]3 years ago

5 0

Answer:

The ossicles (the three tiny bones in the middle ear) are responsible for __________.

A.converting sound vibrations into neural signals

B.relaying sound vibrations to the eardrum

C.vibrating in response to sound waves

D.amplifying sound vibrations from the eardrum

Hope this helps

Feliz [49]3 years ago

3 0

Answer:

D.amplifying sound vibrations from the eardrum

this is correct

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A comet is traveling through space with speed 3.01 ✕ 104 m/s when it encounters an asteroid that was at rest. The comet and the

Tcecarenko [31]

Answer: $8.493(10)^{-3} m/s$

Explanation:

According to the conservation of linear momentum principle, the initial momentum $p_{i}$ (before the collision) must be equal to the final momentum $p_{f}$ (after the collision):

$p_{i}=p_{f}$ (1)

In addition, the initial momentum is:

$p_{i}=m_{1}V_{1}+m_{2}V_{2}$ (2)

Where:

$m_{1}=1.71(10)^{14} kg$ is the mass of the comet

$m_{2}=6.06(10)^{20} kg$ is the mass of the asteroid

$V_{1}=3.01(10)^{4} m/s$ is the velocity of the comet, which is positive

$V_{2}=0 m/s$ is the velocity of the asteroid, since it is at rest

And the final momentum is:

$p_{f}=(m_{1}+m_{2})V_{f}$ (3)

Where:

$V_{f}$ is the final velocity

Then :

$m_{1}V_{1}+m_{2}V_{2}=(m_{1}+m_{2})V_{f}$ (4)

Isolating $V_{f}$ :

$V_{f}=\frac{m_{1}V_{1}}{m_{1}+m_{2}}$ (5)

$V_{f}=\frac{(1.71(10)^{14} kg)(3.01(10)^{4} m/s)}{1.71(10)^{14} kg+6.06(10)^{20} kg}$

Finally:

$V_{f}=8.493(10)^{-3} m/s$ This is the final velocity, which is also in the positive direction.

8 0

4 years ago

A bag of sugar weighs 3.50 lb on Earth. What would it weigh in newtons on the Moon, where the free-fall acceleration isone-sixth

Alex73 [517]

Answer:

$F_{Earth}$ = 15.57 N

$F_{Moon}$ = 2.60 N

$F_{Uranus}$ = 16.98 N

The mass of the bag is the same on the three planets. m=1.59 kg

Explanation:

The weight of the sugar bag on Earth is:

g=9.81 m/s²

m=3.50 lb=1.59 kg

$F_{Earth}$ =m·g=1.59 kg×9.81 m/s²= 15.57 N

The weight of the sugar bag on the Moon is:

g=9.81 m/s²÷6= 1.635 m/s²

$F_{Moon}$ =m·g=1.59 kg× 1.635 m/s²= 2.60 N

The weight of the sugar bag on the Uranus is:

g=9.81 m/s²×1.09=10.69 m/s²

$F_{Uranus}$ =m·g=1.59 kg×10.69 m/s²= 16.98 N

The mass of the bag is the same on the three planets. m=1.59 kg

5 0

3 years ago

Carbon monoxide pure substance or mixture and why

Aleks04 [339]

Carbon Monoxide is a mixture because its a simple compound with 2 elements, carbon and oxygen are bonded together

7 0

3 years ago

a low tide and a high tide occur in the oceans two times each day. which factor has the greatest effect on the size of the tides

Dmitrij [34]

Answer:

The gravitational pull from the Moon has the greatest effect on the size of the tides.

Hope this helps, :)

7 0

3 years ago

A conducting sphere of radius R1 carries a charge Q. Another conducting sphere has a radius R2 = 3 4 R1, but carries the same ch

Blizzard [7]

Answer:

The ratio of electric field is 16:9.

Explanation:

Given that,

Radius $R_{2}=\dfrac{3}{4}R_{1}$

Charge = Q

We know that,

The electric field is directly proportional to the charge and inversely proportional to the square of the distance.

In mathematically term,

$E=\dfrac{kQ}{R^2}$

Here, $E\propto\dfrac{1}{R^2}$

We need to calculate the ratio of electric field

Using formula of electric field

$\dfrac{E_{2}}{E_{1}}=\dfrac{R_{1}^2}{R_{2}^2}$

Put the value into the formula

$\dfrac{E_{2}}{E_{1}}=\dfrac{(4R_{1})^2}{(3R_{1})^2}$

$\dfrac{E_{2}}{E_{1}}=\dfrac{16}{9}$

Hence, The ratio of electric field is 16:9.

5 0

4 years ago